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saw5 [17]
3 years ago
5

A. whileto restcomingdown from a slideyou stop and come​

Physics
1 answer:
Pani-rosa [81]3 years ago
3 0
Ok ok ok ok ok ok I ok ok I I’m only on kn knkkkm I’m on
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An aluminium bar 600mm long, with diameter 40mm, has a hole drilled in the center of the bar. The hole is 30mm in diameter and i
arsen [322]

Answer:

Explanation:

l = 600mm = 0.6m

d = 40mm = 0.04m

hd = 30mm = 0.03m (diameter of the hole)

hl = 100mm = 0.1m (hole length)

modulus of elasticity for the aluminium = 85GN/m2

compressive load = 180kN

6 0
3 years ago
4. An object moves in a circular path at a constant speed. Compare the direction of the object’s velocity and acceleration vecto
Vikentia [17]

Answer:

Option C

The vectors are perpendicular

Explanation:

Acceleration will be directed towards the center for uniform circular motion. Consequently, velocity of the object increases hence acceleration. The direction of velocity is tangent to its circular motion, therefore, tangential velocity vector is perpendicular to centripetal acceleration vector. Therefore, comparing the direction of the object, the vectors are perpendicular to each other.

4 0
3 years ago
Based on the image below what would an observer on the nighttime side of earth observe?
sertanlavr [38]
I would love to help; where’s the picture?
3 0
3 years ago
Particles q1, q2, and q3 are in a straight line.
natima [27]

The net force on q2 will be 1.35 N

A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.

Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.

We have to find the net force on q2

At first we will find Force due to q1

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²

F = 450 × 10⁻³

F₁ = 0.45 N (+)

Now we will find Force due to q2

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²

F = 1800 × 10⁻³

F₂ = 1.8 N (-)

So net force (F) will be

F = F₂ - F₁

F = 1.8 - 0.45

F = 1.35 N

Hence the net force on q2 will be 1.35 N

Learn more about force here:

brainly.com/question/25573309

#SPJ10

8 0
2 years ago
What fundamental frequency would you expect from blowing across the top of an empty soda bottle that is 24 cm deep
kari74 [83]

Answer:

708.3 Hz

Explanation:

For an open-air column, like the empty can, the fundamental frequency is given by

f_1 = \frac{v}{2L}

where

v = 340 m/s is the speed of sound

L is the length of the column

In this problem, the length of the bottle is

L = 24 cm = 0.24 m

Therefore, the fundamental frequency is

f_1 = \frac{340 m/s}{2(0.24 m)}=708.3 Hz

8 0
3 years ago
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