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3 years ago

If the mass is 22 g and the volume is 11 ml, what is the density of the object

Physics

2 answers:

andriy [413]3 years ago

8 0

2 g/mL there’s your answer

ratelena [41]3 years ago

3 0

Density= mass/volume
Density= 22/11
Density= 2g/ml

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Can someone please answer this ill give you brainliest and your getting 100 points.

strojnjashka [21]

Answer: i think its b

Explanation:

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2 years ago

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Alden, a passenger on a yacht moored 15 miles due north of a straight, east-west

Ghella [55]

Answer:

To minimize the travel time from the yacht to the hospital, the motorboat should head in a direction of 12.83 degrees west of south.

Explanation:

If we assume that both the motorboat and ambulance will be moving at a constant speed, we can calculate the time that each one will take to travel a given distance using the following equation:

$time=\frac{distance}{speed}$

Then the total travel time from the yacht to the hospital will be the motorboat travel time plus the ambulance travel time

$t=t_m+t_a$

$t=\frac{d_m}{s_m} +\frac{d_a}{s_a}$

First we must write the total travel time in terms of the motorboat's direction (Θ).

$cos(\theta)=\frac{15}{d_m}$

$d_m=\frac{15}{cos(\theta)}=15 sec(\theta)$

$d_a=60-d_1$

$tan(\theta)=\frac{d_1}{15}$

$d_1=15tan(\theta)$

$d_a=60-15tan(\theta)$

$t=t_m+t_a$

$t=\frac{d_m}{s_m} +\frac{d_a}{s_a}$

$t=\frac{15sec(\theta)}{20} + \frac{60-15tan(\theta)}{90}$

$t=\frac{15}{20}sec(\theta) + \frac{60}{90}-\frac{15}{90}tan(\theta)$

$t=\frac{3}{4}sec(\theta)-\frac{1}{6}tan(\theta) + \frac{2}{3}$

So this last equation represents the variation of the total travel time as a function of the motorboat's direction.

To find the equation's minimum point (which would be the direction with the minimum total travel time), we must find $\frac{dt}{d\theta}$ and then find its roots (its x-interceptions).

$\frac{dt}{d\theta}=\frac{d}{d\theta} (\frac{3}{4}sec(\theta)-\frac{1}{6}tan(\theta) + \frac{2}{3})$

$\frac{dt}{d\theta}=\frac{3}{4}sec(\theta)tan(\theta)-\frac{1}{6}sec^2(\theta)$

$\frac{dt}{d\theta}=sec(\theta)(\frac{3}{4}tan(\theta)-\frac{1}{6}sec(\theta))$

Now let's find the values of x which make $\frac{dt}{d\theta}=0$

$\frac{dt}{d\theta}=sec(\theta)(\frac{3}{4}tan(\theta)-\frac{1}{6}sec(\theta))=0$

As sec(\theta) is never equal to zero, then $\frac{dt}{d\theta}$ would be zero when

$\frac{3}{4}tan(\theta)=\frac{1}{6}sec(\theta)$

Graphing both equations we can find their interceptions and this would the value we're looking for.

In the attached images we can see that \theta=0.224 rad=12.83° is the minimum point for $t(\theta)$ . Then, to minimize the travel time from the yacht to the hospital, the motorboat should head in a direction of 12.83 degrees west of south.

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Answer:

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3 years ago

Are the units of the formula ma = mv2/2 dimensionally consistent? Select the single best answer.

Vesnalui [34]

To solve the problem we will simply perform equivalence between both expressions. We will proceed to place your units and develop your internal operations in case there is any. From there we will compare and look at its consistency

$ma = \text{Mass}\times \text{Acceleration}$

$ma = kg \cdot \frac{m}{s^2}$

At the same time we have that

$\frac{1}{2}mv^2 = \text{Mass}\times \text{Velocity}^2$

$\frac{1}{2}mv^2 = kg ( \frac{m}{s})^2$

$\frac{1}{2}mv^2 = kg \cdot \frac{m^2}{s^2}$

Therefore there is not have same units and both are not consistent and the correct answer is B.

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