Answer:
- Work done is maximum when the movement of object is in line and direction of force.
OR
- Work done is maximum, when displacement takes place along the direction of force.
- Work done is given by the equation
W = F.S
<em> W = F. S cos Θ</em>
<em>When cos Θ = 0° ; cos 0 = 1</em>
Answer:
Acceleration a=0.5 m/s²
Explanation:
Given data
Mass m=12,900 kg=1.29×10⁴kg
Thrust of engine F=28,000 N=2.8×10⁴N
gravitational acceleration g=1.67 m/s²
To find
Acceleration
Solution
As we know that
The net force can be given as
From Newtons second law of motion we know that
Velocity = distance/time
v = (35)/(1/2)
v = 70 km/h
60 km/h for 25 minutes
25 minutes = 25/60 hour
distance= velocity * time
d =(60) * (25/60)
d = 25 km
ΔV = { V(initial) - V(final) } / time
v= (70-60) / (45/60)
average velocity = 13.33 km/h
avg veloticy = 3.7 m/s
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Answer:
The capacitor having less distance of separation has a stronger electric field.
Explanation:
The capacitors are identical and only difference between them is that one has twice the plate separation of the other. Therefore, capacitance of the given capacitors C1 and C2 is,
C1= Aε/d and C2=Aε/2d
The charges Q1 and Q2 on the capacitors of capacitance C1 and C2 respectively, is then given by the equation,
Q1=VC1
Q1=VAε/d
Q2=VC2
Q2=VAε/2d
Therefore, the surface charge density σ1 and σ2 for the capacitors is,
σ1=Q1/A
σ1=VAε/(d*A)
σ1=Vε/d
Similarly,
σ2=Q2/A
σ2=Vε/2d
The electric field between the plates is directly proportional to the surface charge density. And so electric field is inversely proportional to the distance of separation. Therefore the capacitor whose distance of separation is less has a stronger electric field.
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