The part of the mantle called the ___ is made out of soft rock that bends like plastic

If a car has an initial velocity of 20 m/s and accelerates at 2.0 m/s2 for 100 m, what is its final velocity?

rodikova [14]

Answer:

28.28 ms-1

Explanation:

v² = u² + 2as

v² = 20² + 2×2×100

v²= 800

v = 28.28 ms-1

3 0

3 years ago

(8 points) Air is used as the working fluid in a simple ideal Brayton cycle that has a pressure ratio of 12, a compressor inlet

trapecia [35]

Answer:

a ) $\dot m = 351.49 kg/s$

b) $\dot m_{actual} = 1046.15 kg/s$

Explanation:

given data:

pressure ration rp = 12

inlet temperature = 300 K

TURBINE inlet temperature = 1000 K

AT the end of isentropic process (compression) temperature is

$\frac{T_2'}{T_1} = rp ^{\frac{\gamma -1}{\gamma}}$

$\frac{T_2'}{300} = 12^{\frac{1.4 -1}{1.4}}$

$T_2' = 610.181 K$

AT the end of isentropic process (expansion) temperature is

$\frac{T_3}{T_4'} = rp ^{\frac{\gamma -1}{\gamma}}$

$\frac{1000'}{T_4'} = 12^{\frac{1.4 -1}{1.4}}$

$T_4' = 491.66 K$

isentropic work is given as

$w(compressor) = CP (T_2' -T_1)$

w = 1.005(610.18 - 300)

w = 311.73 kJ/kg

w(turbine) = 1.005( 1000 - 491.66)

w(turbine) = 510.88 kJ/kg

a) mass flow rate for isentropic process is given as

$\dot m = \frac{70000}{510.88 - 311.73}$

$\dot m = 351.49 kg/s$

b) actual mass flow rate uis given as

$\dot m_{actual} = \frac{70000}{51.088\times 0.85 - \frac{311.73}{0.85}}$

$\dot m_{actual} = 1046.15 kg/s$

6 0

3 years ago

A ball rolls off a table with a horizontal velocity of 3 m/s. If it takes 0.3 seconds for the ball to reach the floor, how high

LekaFEV [45]

The height of the table above the ground is 0.45 m.

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

Horizontal velocity (u) = 3 m/s
Time (t) = 0.3 s
Acceleration due to gravity (g) = 10 m/s²
Height (h) =?

<h3>How to determine the height </h3>

The height of the table can be obtained by using the following formula:

h = ½gt²

h = ½ × 10 × 0.3²

h = 5 × 0.09

h = 0.45 m

Thus, the height of the table is 0.45 m

Learn more about motion under gravity:

brainly.com/question/26275209

6 0

2 years ago

A 30-kg child sits at the top of a 3-meter slide. After sliding down, the child is traveling 4 m/s. How much PE does he start wi

Jobisdone [24]

At the top:

   Potential Energy = (mass) x (gravity) x (height)

   = (30 kg) x (9.8 m/s²) x (3 meters)

   = 882 joules

At the bottom:

   Kinetic Energy = (1/2) x (mass) x (speed)²

   = (1/2) x (30 kg) x (3 m/s)²

   = (15 kg) x (9 m²/s²)

   = 135 joules .

He had 882 joules of potential energy at the top,
but only 135 joules of kinetic energy at the bottom.

Friction stole (882 - 135) = 747 joules of his energy while he slid down.
The seat of his jeans must be pretty warm.

6 0

3 years ago

A current of 0.92 a flows in a wire. how many electrons are flowing past any point in the wire per second? the charge on one ele

Fantom [35]

The current is defined as the ratio between the charge Q flowing through a certain point of a wire and the time interval, $\Delta t$ :
$I= \frac{Q}{\Delta t}$
First we need to find the net charge flowing at a certain point of the wire in one second, $\Delta t=1.0 s$ . Using I=0.92 A and re-arranging the previous equation, we find
$Q=I \Delta t= (0.92 A)(1.0 s)=0.92 C$

Now we know that each electron carries a charge of $e=1.6 \cdot 10^{-19} C$ , so if we divide the charge Q flowing in the wire by the charge of one electron, we find the number of electron flowing in one second:
$N= \frac{Q}{q} = \frac{0.92 C}{1.6 \cdot 10^{-19} C}=5.75 \cdot 10^{18}$

3 0

3 years ago