Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
Y=-2x+4 and y=-2x-5 (mark brainliest plss)
PL= sqrt(4^2+12^2)=4sqrt(1+9)=4sqrt(10)
Using similarity gives that AM=4/3.
ML=40/3
[PLMU]=40/3 * 4 = 160/3 (53.33)
Or
PM= sqrt(4^2+16/9)=sqrt(160/9)=4sqrt(10)/3
4sqrt(10)*4sqrt(10)/3=160/3 or approximately 53.33
Answer: 6 units
Step-by-step explanation:
The line that goes through half of the circle at the top is the radius. Hope this helps!’