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2 years ago

Question 1 (1 point)

Physics

1 answer:

kipiarov [429]2 years ago

6 0

When you go to bed, you should ensure the mattress you sleep on is not too flat

Due to the fact that they frequently achieve a comfortable balance between pressure relief and support, medium-firm mattresses are a great option for combo sleepers. They are both hard enough to support the hips while sleeping on the back and soft enough to relieve pressure on the shoulders when doing so on the side.

<h3>What is a Mattress ?</h3>

A mattress is a sizable, typically rectangular pad used to support someone who is lying down. It is made to be used as a bed or as a component of a bed when mounted on a bed frame.

In general, heavier individuals like firmer beds. Soft foams could be too prone to sinking in for adequate comfort. Lighter people tend to prefer soft to medium firm mattresses because they tend to sink in less and find firm beds to be uncomfortable.

Learn more about Mattress here:

brainly.com/question/28217401

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3 years ago

Help plz I don't understand

Vika [28.1K]

#78

Airplane start with initial speed

$v_i = 0$

now the takeoff velocity is given as

$v_f = 300 km/h$

$v_f = 83.33 m/s$

acceelration is given as

$a = 1 m/s^2$

now we have

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$t = 83.33 s$

#79

Airplane start with initial speed

$v_i = 0$

now the takeoff velocity is given as

$v_f = 300 km/h$

$v_f = 83.33 m/s$

acceelration is given as

$a = 2 m/s^2$

now we have

$v_f - v_i = at$

from above equation we have

$83.33 - 0 = 2(t)$

$t = 41.7 s$

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4 years ago

Which one is an accurate description of he process of erosion

Murljashka [212]

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4 years ago

Read 2 more answers

A disk with radius R and uniform positive charge density s lies horizontally on a tabletop. A small plastic sphere with mass M a

Yanka [14]

Answer:

a. F = Qs/2ε₀[1 - z/√(z² + R²)] b. h = (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

Explanation:

a. What is the magnitude of the net upward force on the sphere as a function of the height z above the disk?

The electric field due to a charged disk with surface charge density s and radius R at a distance z above the center of the disk is given by

E = s/2ε₀[1 - z/√(z² + R²)]

So, the net force on the small plastic sphere of mass M and charge Q is

F = QE

F = Qs/2ε₀[1 - z/√(z² + R²)]

b. At what height h does the sphere hover?

The sphere hovers at height z = h when the electric force equals the weight of the sphere.

So, F = mg

Qs/2ε₀[1 - z/√(z² + R²)] = mg

when z = h, we have

Qs/2ε₀[1 - h/√(h² + R²)] = mg

[1 - h/√(h² + R²)] = 2mgε₀/Qs

h/√(h² + R²) = 1 - 2mgε₀/Qs

squaring both sides, we have

[h/√(h² + R²)]² = (1 - 2mgε₀/Qs)²

h²/(h² + R²) = (1 - 2mgε₀/Qs)²

cross-multiplying, we have

h² = (1 - 2mgε₀/Qs)²(h² + R²)

expanding the bracket, we have

h² = (1 - 2mgε₀/Qs)²h² + (1 - 2mgε₀/Qs)²R²

collecting like terms, we have

h² - (1 - 2mgε₀/Qs)²h² = (1 - 2mgε₀/Qs)²R²

Factorizing, we have

[1 - (1 - 2mgε₀/Qs)²]h² = (1 - 2mgε₀/Qs)²R²

So, h² = (1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]

taking square-root of both sides, we have

√h² = √[(1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]]

h = (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

4 0

3 years ago