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anygoal [31]
3 years ago
9

Which one is an accurate description of he process of erosion

Physics
2 answers:
Mrrafil [7]3 years ago
5 0

Answer:

Erosion is the constant gnawing, erosion and degradation that occurs on the earth's surface. That is, when external geological forces, such as rivers, glaciers, flowing water, winds or waves, carry along and gnaw rock particles and move material from one location on the earth's surface to another.

The rate of erosion is influenced by climate, topography, the extent of vegetation cover and the properties of the loads. Deforestation and cultivation methods that change the soil structure, for example, make the soil harder so that it does not drain away water so quickly, can increase the erosion rate and cause major damage. It is estimated that 30-40 billion tonnes of land is eroded each year from the world's agricultural areas.

Murljashka [212]3 years ago
3 0
<span>Moving bits of rock and soil across the earth’s surface by water, wind, or glaciers.  </span>Erosion is the process by which the earth surface gets worn down.
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Where c is a constant that depends on the initial gas pressure behind the projectile. The initial position of the projectile is
Ronch [10]

Complete Question

A gas gun uses high pressure gas tp accelerate projectile through the gun barrel.

If the acceleration of the projective is : a = c/s m/s​2

Where c is a constant that depends on the initial gas pressure behind the projectile. The initial position of the projectile is s= 1.5m and the projectile is initially at rest. The projectile accelerates until it reaches the end of the barrel at s=3m. What is the value of the constant c such that the projectile leaves the barrel with velocity of 200m/s?

Answer:

The value of the constant is  c = 28853.78 \ m^2 /s^2

Explanation:

From the question we are told that

         The acceleration is  a =  \frac{c}{s}\   m/s^2

         The  initial position of the projectile is s= 1.5m

         The final position of the projectile is s_f =  3 \ m

          The velocity is  v = 200 \ m/s

     Generally  time  =  \frac{ds}{dv}

   and  acceleration is a =  \frac{v}{time }

so

            a = v  \frac{dv}{ds}

 =>        vdv  =  a ds

             vdv  = \frac{c}{s}  ds

integrating both sides

           \int\limits^a_b  vdv  = \int\limits^c_d \frac{c}{s}  ds

Now for the limit

          a =  200 m/s

             b = 0 m/s  

         c = s= 3 m

          d =s_f= 1.5 m

So we have  

           \int\limits^{200}_{0}  vdv  = \int\limits^{3}_{1.5} \frac{c}{s}  ds

              [\frac{v^2}{2} ] \left | 200} \atop {0}} \right.  = c [ln s]\left | 3} \atop {1.5}} \right.

            \frac{200^2}{2}  =  c ln[\frac{3}{1.5} ]

=>           c = \frac{20000}{0.69315}

              c = 28853.78 \ m^2 /s^2

     

5 0
3 years ago
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