Answer:
a) 3.65 seconds
b) 35.87 m/s
Explanation:
s = Displacement = 65.6 m
u = Initial velocity
v = Final velocity
t = Time taken
a = Acceleration due to gravity = 9.81 m/s² (downward direction is taken as positive and upward is taken as negative)
b) Equation of motion
Initial pop up velocity is 35.87 m/s
a)
It took 3.65 seconds to reach this height
A. Move the candle to the right, or the focal point to the left.
For a convex lens, the closer an object is to the focal point, the larger it’s image is (and therefore the greater the magnification is). The two ways you could make the candle be closer to the focal point are to move the candle to the right, or the focal point to the left.
The final velocity of the train after 8.3 s on the incline will be 12.022 m/s.
Answer:
Explanation:
So in this problem, the initial speed of the train is at 25.8 m/s before it comes to incline with constant slope. So the acceleration or the rate of change in velocity while moving on the incline is given as 1.66 m/s². So the final velocity need to be found after a time period of 8.3 s. According to the first equation of motion, v = u +at.
So we know the values for parameters u,a and t. Since, the train slows down on the slope, so the acceleration value will have negative sign with the magnitude of acceleration. Then
v = 25.8 + (-1.66×8.3)
v =12.022 m/s.
So the final velocity of the train after 8.3 s on the incline will be 12.022 m/s.
Answer:
1) true
2) false
3) false
4) true
5) true
6) true
7) true
8) false
9) true
10) false
i think these are correct if im wrong on a few im sorry. Hope this helps at least a bit. And if i do get some wrong you know just to pick the opposite answer.
Answer:
FORCE - rate of change of momentum, ie its changing velocity [change in velocity is of more concern] NEWTON
WORK - product of force and displacement, ie [velocity may be constant or variable but change in position with certain force is of more concern] JOULES
I hope you understood from this..
