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lutik1710 [3]
3 years ago
12

Which statement about a HORIZONTAL projectile is false?

Physics
1 answer:
julsineya [31]3 years ago
7 0

Answer:

the vertical velocity is constant.

Explanation:

The horizontal velocity of a projectile is constant (a never changing in value), There is a vertical acceleration caused by gravity; thus, the vertical velocity of a projectile changes. and the horizontal motion of a projectile is independent of its vertical motion.

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6 0
2 years ago
Someone please help its a simple power problem.
SOVA2 [1]
Well 200 doubled or (x2)=400 if that’s what it means
7 0
3 years ago
A car that experiences no frictional force is started and caused to move. For the car to continue in that motion, the gas pedal
astraxan [27]

Explanation:

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8 0
3 years ago
A ball has an electric charge of +1.5 × 10-9 coulombs. At what distance from the ball's center is the electric field strength eq
dimaraw [331]
E=Fe/q                                                      
5.8x10^5N/C=Fe/(1.5x10^-9C)             
Fe=(5.8x10^5N/C)(1.5x10^-9C)
Fe=8.7x10^-4N

Fe=kq1q2/r²
8.7X10^-4N=(8.99x10^9N·m²/C²)(1.5x10^-9C)(1.5x10-9C)/r²
r²=(8.99x10^9N·m²/C²)(1.5x10^-9C)(1.5x10-9C)/(8.7x10^-4N)
√r²=√0.00002325
The final answer is r=4.8x10-3m

5 0
4 years ago
Read 2 more answers
If the mass is displaced 0.270 m from equilibrium and released, what is its speed when it is 0.130 m from equilibrium?
puteri [66]

Answer:

The speed is 1.52 m.

Explanation:

Given that,

Displacement =0.270 m

Distance = 0.130 m

Suppose a 0.321-kg mass is attached to a spring with a force constant of 13.3 N/m.

We need to calculate the angular velocity

Using formula of angular velocity

\omega=\sqrt{\dfrac{k}{m}}

Put the value into the formula

\omega=\sqrt{\dfrac{13.3}{0.321}}

\omega=6.43\ rad/s

We need to calculate the velocity

Using formula of velocity

v=\omega\sqrt{A^2-x^2}

Put the value into the formula

v=6.43\times\sqrt{0.270^2-0.130^2}

v=1.52\ m/s

Hence, The speed is 1.52 m.

6 0
3 years ago
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