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2 years ago

11

X = y - 3

1 answer:

Mumz [18]2 years ago

5 0

The answer to this is B.

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Find the savings plan balance after 2 years with an APR of 4% and monthly payments of $250. The balance is $ (Do not round until

alexdok [17]

Answer:

$6,506.51

Step-by-step explanation:

Recall that increasing an amount C in x% is equivalent to multiply it by (1+x/100)

As we have 4% APR, the monthly interest would be (4/12)% = 0.04/12

<u>Month 0</u> (first payment)

$250

Month 1

$250 + 250 \frac{0.04}{12}= 250(\frac{12.04}{12})$

<u>Month 2</u>

$250(1+\frac{12.04}{12}+(\frac{12.04}{12})^2)$

<u>Month 3</u>

$250(1+\frac{12.04}{12}+(\frac{12.04}{12})^2+(\frac{12.04}{12})^3)$

<u>Month 24 (2 years)</u>

$250(1+\frac{12.04}{12}+(\frac{12.04}{12})^2+(\frac{12.04}{12})^3+...+(\frac{12.04}{12})^{24})$

The sum

$1+\frac{12.04}{12}+(\frac{12.04}{12})^2+(\frac{12.04}{12})^3+...+(\frac{12.04}{12})^{24}$

is the sum of the first 24 terms of a geometric sequence with common ratio $\frac{12.04}{12}$ which is

$\frac{1-(12.04/12)^{25}}{1-(12.04/12)}=26.02603071$

so, after 2 years the saving balance is

250*26.02603071 = 6,506.50767= $6,506.51 rounded to the nearest cent.

6 0

2 years ago

What is the x-intercept?

Akimi4 [234]

x - intercept is (-4,0)

7 0

2 years ago

Read 2 more answers

PLEASE HELP BEEN HERE for 30 minutes. GET A EASY 10 points!

steposvetlana [31]

The answer is -- A. Exactly one solution

6 0

2 years ago

Triangles ABC and DEF are similar.

vivado [14]

All I can really remember is find the scale factor and divide it by the segment

3 0

2 years ago

Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).

fomenos

Answer:

$\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1$

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is $2a=|4--10|$ .

$\implies 2a=|14|$

$\implies 2a=14$

$\implies a=7$

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is $(\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)$

We need to use the relation $a^2+b^2=c^2$ to find $b^2$ .

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

$c=|6--3|=9$

$\implies 7^2+b^2=9^2$

$\implies b^2=9^2-7^2$

$\implies b^2=81-49$

$\implies b^2=32$

We substitute these values into the standard equation of the hyperbola to obtain:

$\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1$

$\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1$

7 0

2 years ago