When hockey players push the puck along the ice it slides causing heat which melts the ice causing the friction against the ice to be less.
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Answer:
the average force exerted by seatbelts on the passenger is 5625 N.
Explanation:
Given;
initial velocity of the car, u = 50 m/s
distance traveled by the car, s = 20 m
final velocity of the after coming to rest, v = 0
mass of the passenger, m = 90 kg
Determine the acceleration of the car as it hit the pile of dirt;
v² = u² + 2as
0 = 50² + (2 x 20)a
0 = 2500 + 40a
40a = -2500
a = -2500/40
a = -62.5 m/s²
The deceleration of the car is 62.5 m/s²
The force exerted on the passenger by the backward action of the car is calculated as follows;
F = ma
F = 90 x 62.5
F = 5625 N
Therefore, the average force exerted by seatbelts on the passenger is 5625 N.
Answer:
Explanation:
The condition for translation equilibrium is that is that the net force acting on the body must be zero.
The sum all the external forces acting on the body in horizontal as well as vertical direction must be zero.
∑Fₓ=0 and ∑Fy=0
now if the above two condition are satisfied the rigid body is said to be in translational equilibrium.
God bless... hope this help to clear your doubt.
