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RoseWind [281]
3 years ago
12

Galaxies are classified based on their a. shape. c. stars. b. color. d. age.

Physics
2 answers:
ArbitrLikvidat [17]3 years ago
7 0
<span> the answer is shape.</span>
Bogdan [553]3 years ago
7 0

Answer:

The answer is shape

Explanation:

Just took the test

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Consult Multiple Concept Example 10 in preparation for this problem. Traveling at a speed of 18.2 m/s, the driver of an automobi
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The speed of the automobile after 1.43s is 10 \frac{m}{s}

Explanation:

a= \frac{-f}{m}= \frac{-u_{k}*m*g}{m}

a= -u_{k}*g=- 0.590* 9.8 \frac{m}{s^{2} }= -5.782 \frac{m}{s^{2} }

V_{f} = V_{i} + a*t

V_{f} = 18.2 \frac{m}{s} - (5.782 \frac{m}{s^{2} }* 1.43 s)

V_{f} = 9.93174 \frac{m}{s}

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3 years ago
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A Planet, such as (pluto)
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A car generator turns at 400 rpm (revolutions per minute) when the engine is idling. It has a rectangular coil with 300 turns of
Sav [38]

The field strength needed to produce a 24.0 V peak emf is 0.73T.

To find the answer, we need to know about the expression of emf.

What's the expression of peak emf produced in a rotating rectangular loops?

  • The peak emf produced in a rotating loops= N×B×A×w
  • N= no. of turns of the loop, B= magnetic field, A= area of loop and w= angular frequency
  • So, B = emf/(N×A×w)
<h3>What's the magnetic field applied to the loop, when rectangular coil with 300 turns of dimensions 5.00 cm by 5.22 cm rotates at 400 rpm produce a 24.0 V peak emf?</h3>
  • N= 300, A= 5cm × 5.22cm = 0.05m × 0.0522m = 0.00261 m²
  • Emf= 24V, w= 2π×400 rpm= 2π×(400rps/60) = 42 rad/s
  • Now, B= 24/(300×0.00261×42)

B= 24/(300×0.00261×42) = 0.73T

Thus, we can conclude that the magnetic field is 0.73T.

Learn more about the electromagnetic force here:

brainly.com/question/13745767

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6 0
2 years ago
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solmaris [256]

Answer:

i think your answer is C

Explanation:

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