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Studentka2010 [4]
1 year ago
5

What chemical bonds stabilize the different structures in primary, secondary, tertiary and quaternary structures?.

Chemistry
1 answer:
Blababa [14]1 year ago
4 0

Peptide bonds, hydrogen bonds, disulfide linkages, van der Waals, and electrostatic forces of attraction are the chemical bonds that stabilize the different structures in primary, secondary, tertiary, and quaternary structures.

The advanced structure of proteins gives rise to two kinds of major molecular shapes which are fibrous as well as globular structures. The main forces which are involved in stabilizing the secondary along with the tertiary structures of proteins include hydrogen bonds, disulfide type linkages, van der Waals attraction, and electrostatic forces of attraction.

The primary structure is generally determined by adjoining peptide bonds where the link is adjoining amino acids in sequential order. Tertiary structure is determined by the existence of disulfide bonds in between hydrophobic interactions as well as cysteine residues whereas the quaternary type structure is determined by multiple subunits of a protein that undergo various interactions.

Hydrogen bonds exist in a protein molecule as its large number can form between adjacent regions of the polypeptide chain in folded form and stabilize its three-dimensional kind of shape.

Learn to know more about levels of protein structure on

brainly.com/question/17338734

#SPJ4

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Which of the following is NOT a clue that a chemical change has occurred? * 1 point Sugar turns blackish-brown as it is heated.
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CHEMISTRY HELP<br> Once the following equation is balanced, what is the correct coefficient for Z₂?
yawa3891 [41]

Answer:

The coefficient of Z₂ is 1.

Explanation:

From the question given above:

X + ZY —> XY + Z₂

Next, we shall balance the equation to obtain the coefficient of Z₂. This can be obtained as follow:

X + ZY —> XY + Z₂

There is 1 atom of Z on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of ZY as shown below:

X + 2ZY —> XY + Z₂

There are 2 atoms of Y on the left side and 1 atom on the right side. It can be balance by putting 2 in front of XY as shown below:

X + 2ZY —> 2XY + Z₂

Now, we have 1 atom of X on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of X as shown below:

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8 0
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Question 7
astraxan [27]

Answer:

tama yon sagot nya gayahin mo nalang

8 0
3 years ago
Imagine the reaction A + B ⇌ C + D is at equilibrium, where the forward and reverse reactions are at equal rates. What would hap
kondaur [170]

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Rate of forward reaction will increase.

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Effect of change in reaction condition on equilibrium is explained by Le Chatelier's principle. According to this principle,

If an equilibrium condition of a dynamic reversible reaction is disturbed by changing concentration, temperature, pressure, volume, etc,  then reaction will move will in a direction which counteract the change.

In the given reaction,

A + B ⇌ C + D

If concentration of A is increase, then reaction will move in a direction which decreases the concentration of A to reestablish the equilibrium.

As concentration A decreases in forward direction, therefore, rate of forward reaction will increase.

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3 years ago
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