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Anna007 [38]
3 years ago
10

Please help with my science ?

Chemistry
1 answer:
fredd [130]3 years ago
7 0
Abrasion is the mechanical scraping of a rock surface by friction between rocks and moving particles during their transport by wind,glacier, waves, gravity and running water or erosion.
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given two equations representing reactions: which type of reaction is represented by each of these equations?
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Answer:

Equation 1 - nuclear fission

Equation 2 - nuclear fusion

Explanation:

Nuclear fission is a reaction in which a large nucleus is split into smaller nuclei when it is bombarded by neutrons. The process produces more neutrons to continue the chain reaction. This is clearly depicted in equation 1 as shown in the question.

Nuclear fusion is a reaction in which two light nuclei combine in order to form a larger nuclei. This is clearly depicted in equation 2 as shown in the question.

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What group is helium in? Group 8 or group 2?
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How many grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C?
jolli1 [7]

Answer:

22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C

Explanation:

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law:

P * V = n * R * T

where R is the molar constant of the gases and n the number of moles.

In this case you know:

  • P= 7.5 atm
  • V= 2.3 L
  • n= ?
  • R= 0.082 \frac{atm*L}{mol*K}
  • T= 24 °C= 297 °K (being 0°C=273°K)

Replacing:

7.5 atm* 2.3 L=n*0.082 \frac{atm*L}{mol*K} *297K

Solving:

n=\frac{7.5 atm* 2.3 L}{0.082 \frac{atm*L}{mol*K} *297K}

n=0.708 moles

Knowing that oxygen gas is a diatomic gas of molecular form O₂ and its mass is 32 g / mole, you can apply the following rule of three: if 1 mole contains 32 grams, 0.708 moles, how much mass will it have?

mass=\frac{0.708 moles*32 grams}{1mole}

mass= 22.656 grams

<u><em>22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C</em></u>

8 0
3 years ago
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