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Anna007 [38]
3 years ago
10

Please help with my science ?

Chemistry
1 answer:
fredd [130]3 years ago
7 0
Abrasion is the mechanical scraping of a rock surface by friction between rocks and moving particles during their transport by wind,glacier, waves, gravity and running water or erosion.
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How many atoms total are present in one molecule of 5-methyl-2 hexanol C7H16O
muminat

Answer:

24 atoms

Explanation:

The formula of the compound is C₇H₁₆O

The number of atoms that makes up one molecule of this compound are:

7 carbon atoms

16 hydrogen atoms

1 oxygen atom

The total number of atoms = 7+16+1 = 24 atoms

3 0
3 years ago
Quantitative was to measure light intensity
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One candela per steradian is termed a lumen, which is the measure of light intensity people are most familiar with One foot candle is equivalent to one lumen per square foot
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2 years ago
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How do particles in matter change when a substance becomes hotter, cool down, or changes state?
Nana76 [90]

Answer:

When heat is added to a substance, the molecules and atoms vibrate faster. As atoms vibrate faster, the space between atoms increases. The motion and spacing of the particles determines the state of matter of the substance. The end result of increased molecular motion is that the object expands and takes up more space.

hope this helps!!!!!!

3 0
3 years ago
what would be the ph of an aqueous solution of sulphuric acid which is 5×10^_5 mol l^_1 in concentration​
guajiro [1.7K]

Answer:

the ph of an aqueous solution of sulphuric acid which is 5*10^5 mol in concentration is basic in nature

6 0
3 years ago
A 25.00 mL sample of the ammonia solution
musickatia [10]

Answer:

1.634 molL-1

Explanation:

The mol ration between NH3 and HCl is 1 : 1

Using Ca Va / Cb Vb = Na / Nb   where a = acid and b = base

Na = 1

Nb = 1

Ca = 0.208 molL-1

Cb = ?

Va = 19.64 mL

Vb = 25.00mL

Solving for Cb

Cb = Ca Va / Vb

Cb = 0.208 * 19.64 / 25.0

Cb = 0.1634 molL-1 (Concentration of diluted ammonia solution)

Using the dilution equation;

C1V1 = C2V2

Initial Concentration, C1 = ?

Initial Volume, V1 = 25.00 mL

Final Volume, V2 =  250 mL

Final Concentration, C2 = 0.1634 molL-1

Solving for C1;

C1 = C2 * V2 / V1

C1 = 0.1634 * 250 / 25.00

C1 = 1.634 molL-1

3 0
3 years ago
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