Explanation:
If a positive test charge is placed in an electric field, it will exert the force in the test charge in the direction of electric field vector. We know that the direction of electric field is given by electric field lines. The field lines for a positive charge is outwards. The electric force acting on the charge is given by :
F = q E
Hence, this is the required solution.
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Explanation:
Answer:
8 J
Explanation:
Heat = work + change in internal energy
Q = W + ΔU
15 J = 7 J + ΔU
ΔU = 8 J
(a) PE = 0.016J
(b) PE = 1470J
Explanation:
Given:
Mass, m = 4 kg
distance, x = 0.12 m
Spring constant, k = 2.3N/m
Potential energy, PE = ?
We know:
![PE = \frac{1}{2} kx^2](https://tex.z-dn.net/?f=PE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20kx%5E2)
On substituting the value we get:
![PE = \frac{1}{2} X 2.3 X (0.12)^2\\\\PE = 0.016J](https://tex.z-dn.net/?f=PE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20X%202.3%20X%20%280.12%29%5E2%5C%5C%5C%5CPE%20%3D%200.016J)
(b)
Mass, m = 10kg
Height, h = 15m
Potential energy, PE = ?
Acceleration due to gravity, g = 9.8 m/s²
![PE = mgh\\\\PE = 10 X 15 X 9.8\\\\PE = 1470J](https://tex.z-dn.net/?f=PE%20%3D%20mgh%5C%5C%5C%5CPE%20%3D%2010%20X%2015%20X%209.8%5C%5C%5C%5CPE%20%3D%201470J)