Answer:
x = 25 / μ [ ft]
Explanation:
To solve this exercise we can use Newton's second law.
Let's set a reference system where the x axis is parallel to the road
Y axis
N_B + N_A - W_van - W_load = 0
N_B + N_A = W_van + W_load
X axis
fr = ma
a = fr / m
the total mass is
m = (W_van + W_load) / g
the friction force has the expression
fr = μ N_{total}
fr = μy (W_van + W_load)
we substitute
a = μ (W_van + W_load) 
a = μ g
taking the acceleration let's use the kinematic relations where the final velocity is zero
v² = v₀² - 2 a x
0 = v₀² -2a x
x = 
x = 
x = 
x = 25 / μ [ ft]
Answer:
19.01 N
Explanation:
F = Force being applied to the crate = 45 N
= Angle at which the force is being applied = 
Horizontal component of force is given by
The horizontal component of the force acting on the crate is 19.01 N.
Answer:
Velocidad = 2 m/s
Explanation:
Dados los siguientes datos;
Distancia = 80 m
Tiempo = 40 s
Para encontrar la velocidad del automóvil;
La velocidad se puede definir como la tasa de cambio en el desplazamiento (distancia) con el tiempo.
La velocidad es una cantidad vectorial y, como tal, tiene magnitud y dirección.
Matemáticamente, la velocidad viene dada por la ecuación;
Sustituyendo en la fórmula, tenemos;
Velocidad = 80/40
Velocidad = 2 m/s
Answer: 6
Explanation:
Have an awesome amazing day
Answer:
The mass of object is 300g.
Its weight on earth is W×0.3kg×9.8m/s2=2.94 N
Its weight on moon is A 300 g would be 48 g on the moon
GOOD LUCK!
