An object 2.2 kg object accelerates at 4.0 m/s^2. What is the mass of the object?
1 answer:
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Explanation:
It is given that,
Mass of the tackler, m₁ = 120 kg
Velocity of tackler, u₁ = 3 m/s
Mass, m₂ = 91 kg
Velocity, u₂ = -7.5 m/s
We need to find the mutual velocity immediately the collision. It is the case of inelastic collision such that,
v = -1.5 m/s
Hence, their mutual velocity after the collision is 1.5 m/s and it is moving in the same direction as the halfback was moving initially. Hence, this is the required solution.
Given data:
* The extension of the steel wire is 0.3 mm.
* The length of the wire is 4 m.
* The area of cross section of wire is,
* The young modulus of the steel is,
Solution:
The young modulus of the steel in terms of the force and extension is,
where F is the force acting on the steel wire,, l is the original length of the wire, dl is the extension of the wire, and A is the area,
Substituting the known values,
Thus, the force which produce the extension of 0.3 mm of the steel wire is 31.5 N.
Answer:
Explanation:
= magnitude of charge on each proton = 1.6 x 10⁻¹⁹ C
= mass of each proton = 1.67 x 10⁻²⁷ kg
r = distance between the two protons = 1 x 10⁻¹⁵ m
Electric force between the two protons is given as
N
Gravitational force between the two protons is given as
N
Ratio is given as