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salantis [7]
3 years ago
10

An object 2.2 kg object accelerates at 4.0 m/s^2. What is the mass of the object?

Physics
1 answer:
KatRina [158]3 years ago
5 0

Answer:

2.2kg

Explanation:

kilograms is a measurement of mass so the answer is 2.2kg

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A balloon is expanded to the same volume as that of a human head. Do an order-of-magnitude estimate of the volume of this balloo
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Answer:

Volume of head = 1000 cm^3

Explanation:

 The head of a normal person can be assumed as a sphere with radius 10 cm.

 Volume of sphere=\frac{4}{3} \pi r^3, where r is the radius.

 We have approximate radius = 10 cm.

  Approximate volume of head =\frac{4}{3}* \pi *10^3=4189 cm^3

 In the given options the closest value to the approximate volume is 1000 cm^3.

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the mass of one water drop is 0.0008kg and the gravitational field strength is 10N/kg what is its weight
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A nuclear fission reactor produces electricity. What is the role of the fuel, the control rods, water, and generator in this pro
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A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calcu
galina1969 [7]

Question:

A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.

(a)60 (b)90 (c)120

Answer:

(a)5.42 N (b)6.26 N (c)5.42 N

Explanation:

From the question

Length of wire (L) = 2.80 m

Current in wire (I) = 5.20 A

Magnetic field (B) = 0.430 T

Angle are different in each part.

The magnetic force is given by

F=I \times B \times L \times sin(\theta)

So from data

F = 5.20 A \times 0.430 T \times 2.80 sin(\theta)\\\\F=6.2608 sin(\theta) N

Now sub parts

(a)

\theta=60^{o}\\\\Force = 6.2608 sin(60^{o}) N\\\\Force = 5.42 N

(b)

\theta=90^{o}\\\\Force = 6.2608 sin(90^{o}) N\\\\Force = 6.26 N

(c)

\theta=120^{o}\\\\Force = 6.2608 sin(120^{o}) N\\\\Force = 5.42 N

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