Question

a radar station detects an airplane approaching directly from the east. at first observation, the range to the plane is 385.0 m at 41.0 °

Answer 1

An airplane flying directly toward it from the east is spotted by a radar station. The distance to the plane at initial observation is 385.0 m at 41.0 °. 302.26m is the displacement.

What is displacement?

Displacement is defined as a shift in an object's position. It is a vector quantity with direction and magnitude. An arrow pointing from the starting location to the finishing position is used to represent it. For instance, if an object moves from position A to position B, its position changes. The term used to describe this change in an object's position is displacement.

The instantaneous velocity of the item is the rate at which the displacement changes as a function of time when studying the motions of objects across time. Therefore, the instantaneous speed is different from the velocity, or the rate at which the distance traveled along a particular path changes over time. The temporal rate of change can also be used to define the velocity. The velocity of P (for example, a point representing the position of a passenger walking on the train) may be referred to as a relative velocity as opposed to an absolute velocity, which is computed with respect to a point which is considered to be "fixed in the space," if one takes into consideration a moving initial position or, equivalently, a moving origin (e.g., an initial position or the origin which is fixed to a train wagon, which in turn moves on its rail track) (such as, for instance, a point fixed on the floor of the train station).

Therefore,

d1= 385.0m

∅ = 41°

and ∅=124° , d2= 795.0m

r1= d1sin∅j+d2cos∅i

  =385sin41°j+795cos41°i

  =252.59j+599.98i

|r1|= $\sqrt{63801.70+359976.00} ( r=\sqrt{a^{2}+b^{2} }$ if |r| = ai+bj)

    =650.98m

similar for r2,

=d1sin124°j+d2cos124°i

=319.16j+(-444..40)i

|r2|=$\sqrt{101863.10+19749.36}$

    =348.72m

so displacement |r2-r1| = 302.26m

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