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weqwewe [10]
2 years ago
5

A plane flies at 400 north of East for 150 miles,then flies 200 miles at an angle of 150 west of North. What is the plane's fina

l displacement? Show all work
Physics
1 answer:
ivanzaharov [21]2 years ago
3 0

Answer:

341.46miles

Explanation:

Find the diagram attachment.

To get the displacement D, we will use the cosine rule as shown;

D² = 200²+150²-2(160)(400)cos65°

D² = 40000+22500-128000cos65°

D² = 62500+54095.14

D² = 116595.14

D = √116595.14

D= 341.46 miles

Hence the plane final displacement is 341.46miles

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Lostsunrise [7]
The force exerted by a magnetic field on a wire carrying current is:
F=ILB \sin \theta
where I is the current, L the length of the wire, B the magnetic field intensity, and \theta the angle between the wire and the direction of B.

In our problem, the force is F=0.20 N. The current is I=1.40 A, while the length of the wire is L=35.0 cm=0.35 m. The angle between the wire and the magnetic field is 53 ^{\circ}, so we can re-arrange the formula and substitute the numbers to find B:
B= \frac{F}{IL \sin \theta}= \frac{0.20 N}{(1.40 A)(0.35 m)(\sin 53^{\circ})}=0.51 T
3 0
3 years ago
While eating lunch high up in a skyscraper, two construction workers calculate their gravitational potential
Maurinko [17]

Answer:

The mass of the other worker is 45 kg

Explanation:

The given parameters are;

The gravitational potential energy of one construction worker = The gravitational potential energy of the other construction worker

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The height level of the lighter construction worker's location = h₁

The height level of the other construction worker's location = h₂ = 2·h₁

The gravitational potential energy, P.E.,  is given as follows;

P.E. = m·g·h

Where;

m = The mass of the object at height

g = The acceleration due to gravity

h = The height at which is located

Let P.E.₁ represent the gravitational potential energy of one construction worker and let P.E.₂ represent the gravitational potential energy of the other construction worker

We have;

P.E.₁ = P.E.₂

Therefore;

m₁·g·h₁ = m₂·g·h₂

h₂ = 2·h₁

We have;

m₁·g·h₁ = m₂·g·2·h₁

m₁ = 2·m₂

90 kg = 2 × m₂

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8 0
2 years ago
A certain pair of slits are separated by a distance d. Monochromatic coherent light falls on this pair of slits and the interfer
DanielleElmas [232]

Answer:

The new separation distance between adjacent bright fringes will be <u>4 mm</u>

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Now, for the second case:

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Therefore,

Δx₂ = λL/(d/2)

Δx₂ = 2(λL/d)

using eqn (1), we get:

Δx₂ = 2 Δx₁

Δx₂ = 2(2 mm)

<u>Δx₂ = 4 mm</u>

5 0
3 years ago
When waves interfere together and result in a quieter sound is called
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That is called fully constructive interference.
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1: Why do the work of scientist cannot be pinned down to a single year?
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It can't be pinned down to a single year because scientific work takes place over many years of research and discovery. 
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