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Leviafan [203]
3 years ago
13

Find the net work done by friction on the body of a snake slithering in a complete circle of radius. The coefficient of friction

between the ground and the snake is 0.25, and the snake's weight is 56.0 N.
A. 590 J
B. 2900 J
C. 0 J
D. 290 J
Physics
1 answer:
Tamiku [17]3 years ago
7 0

Answer:

C. 0 J

Explanation:

When an object moves in a circle, friction provides the centripetal force. Hence, it is acting towards the centre of the circle. The displacement of the object is tangential to the circle at the point of interest. Hence, the angle between the frictional force and the displacement is 90°.

Work done is given by

<em>W</em> = <em>Fd</em> cos <em>θ</em>

where <em>F</em> is the force, <em>d</em> is the displacement and <em>θ</em> is the angle between them.

<em>W</em>  = <em>Fd</em> cos 90° = 0 J

Hence, the work done by friction is 0 J.

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Answer:

Citizens and neighborhood.

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3 years ago
A sound wave with a waveenght of 2.5 meters traves 660 meters in 2 seconds calculate the frequemcy of the wave to cacuation the
finlep [7]

The frequency of the wave is 132 Hz

Explanation:

To calculate the speed of the wave, we can use the following formula:

v = \frac{d}{t}

where

d is the distance travelled by the wave

t is the time elapsed

For the sound wave in this problem, we have:

d = 660 m is the distance travelled

t = 2 s is the time interval considered

Substituting and solving for v, we find the speed of the sound wave:

v=\frac{660}{2}=330 m/s

Now we can calculate the frequency of the wave by using the wave equation:

v=f\lambda

where

v = 330 m/s is the speed of the wave

\lambda=2.5 m is the wavelength

f is the frequency

Solving for f, we find:

f=\frac{v}{\lambda}=\frac{330}{2.5}=132 Hz

Learn more about wavelength and frequency:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

7 0
3 years ago
A block of mass 10 kg and measuring 250 mm on each edge is pulled up an inclined surface on which there is a film of SAE 10W-30
Ivan

Answer:

a) 2.53 * 10^-2 m/s

b) -4.78 * 10^-2 m/s

c)  1.21 * 10^-1 m/s

Explanation:

Given data :

Mass of block = 10 kg

Measuring 250mm on each side

a) calculate the speed  when a force of 75N is applied to pull block upwards

F = f + W sin∅ ( equation for applying the force of equilibrium condition in the x axis )  ----- ( 1 )

f ( friction force )=  ( 16400v * 6.25 *10^-2) =  1025 v

F ( force applied ) = 75

W ( weight of  block ) = 10 * 9.81 = 98.1 N

∅ = 30°

input values into equation 1

V = \frac{75- (98.1*sin30^{0}) }{1025} = 2.53 * 10^-2 m/s

b) Speed when no force is applied on the block

F = f + W sin∅

F = 0

f = 1025 V

W = 98.1 N

∅ = 30°

hence V = \frac{0 - (98.1*sin30^{0}) }{1025} =  - 4.78 * 10^-2 m/s

c) when a force is applied to push block down the incline

F = f + W sin∅ ----- ( 3 )

F = 75 N

f = 1025 V

W = 98.1 N

∅ = 30°

input values into equation 3 considering the fact that the weight of the block is acting in the opposite direction

75 = 1025 V - 98.1 ( sin 30° )

V = \frac{75+( 98.1*sin30^{0})  }{1025} = 1.21 * 10^-1 m/s

5 0
3 years ago
If your mass is 100 kg on earth, what do you weigh on the moon?
galben [10]
You’d weight about 162 N
8 0
3 years ago
Read 2 more answers
Help pls i need this right now
BabaBlast [244]

Answer:

C = - 1.625 i + 6.06 j

Explanation:

Positive angles are measured counterclockwise.

Positive angles are measured counterclockwise. To determine the component on the x axis we use the cosine of the angle while to determine the component on the y axis we use the sine of the angle.

C_{x}=6.28*cos(105)=-1.625\\C_{y}=6.28*sin(105)=6.06\\

C = - 1.625 i + 6.06 j

5 0
3 years ago
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