Find the net work done by friction on the body of a snake slithering in a complete circle of radius. The coefficient of friction
1 answer:
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<u>Answer:</u>
Mass in kg = 39.88
Mass in pounds = 87.92
<u>Explanation:</u>
We have the expression for Density, ρ = Mass / Volume, in this case density is given and we need to find mass and volume.
Volume of a sphere, we have the expression , where r is the radius of sphere.
Radius of sphere, r = Half of diameter = 15/2 = 7.5 cm
So
Mass = Volume * Density = 1767.15*22.57 = 39884.49 g
Mass in kg = 39884.49/1000 = 39.88 kg
Mass in pounds = 39.88*2.205 = 87.92 lb
Your position at time , relative to the stop line:
The Porsche's position:
a. You pass the Porsche immediately after the time it takes for :
at which point you both will have traveled 7.8 m from the stop line.
b. The equation in part (a) has two solutions. The Porsche passes you at the second solution of about , at which point you both will have traveled 29 m.
c. At time , the Porsche is moving at velocity
so that at the moment it passes you, its speed is 13 m/s, which is about 46.8 km/h and below the speed limit, so neither of you will be pulled over.