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ycow [4]
3 years ago
9

Examine the analogy and how it compares a part to a whole. Link : chain :: atom : _[blank]_​ what option best completes this ana

logy? Select all that apply. Molecule matter compound proton
Chemistry
2 answers:
Rzqust [24]3 years ago
7 0

A link is a part of a chain and an atom is a part of a molecule. It is also a part of a compound. Your answer should be molecule and/or compound

Tasya [4]3 years ago
3 0

Answer:  molecule/ compound

Explanation: The given analogy is

Link : chain :: atom : _

As we can see that link is the term which can be used to form a chain. It is a connecting term for link.

Similarly atoms is the term which can be used to define the molecule or the compound. As atom is the tiniest part of the molecule or compound just like the link is the smallest part of the chain.

The best fit analogy out of the give options is molecule/ compound.

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What is the freezing point of a solution of 498mL of water (solute) dissolved in 2.50 L of ethanol (solvent), C2H5OH? The densit
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Answer:

Freezing T° of solution is -142.4°C

Explanation:

This excersise is about colligative properties, in this case freezing point depression,

ΔT = Kf . m . i

Where ΔT = Freezing T° of solvent - Freezing T° of solution

Kf = Cryoscopic constant

m = mol/kg (molality)

i = Number of ions dissolved.

Water is not ionic, so i = 1

Let's find out m.

We determine mass of water, by density

498ml . 1 g/mL = 498 g

We convert the mass of water to moles → 498 g . 1mol/18g = 27.6 moles

We determine mass of solvent by density

2500 mL . 0.789 g/mL = 1972.5 g

Notice, we had to convert L to mL to cancel units.

1 cm³ = 1 mL

We convert the mass from g to kg → 1972.5 g . 1kg /1000g = 1.97kg

We determine m = mol/kg → 27.6mol / 1.97kg = 13.9 m

Kf for ethanol is: 1.99 °C/m

Freezing T° for ethanol is: -114.6°C

We replace at formula: - 114.6°C - Freezing T° solution = 1.99 °C/m . 13.9 m . 1

- 114.6°C - Freezing T° solution = 27.8 °C

- Freezing T° solution  = 27.8°C + 114.6°C

Freezing T° Solution = - 142.4 °C

7 0
2 years ago
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