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kupik [55]
2 years ago
11

Question 52 points) The electromagnetic waves with the highest frequency are ______ waves

Chemistry
1 answer:
Ierofanga [76]2 years ago
8 0

Answer: Gamma Rays

Explanation:

The waves with the highest frequency are Gamma Rays. These electromagnetic waves travel at a very high speed. Best of Luck to you!

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A redox reaction be used as a source of electrical energy only when two half-reactions are physically separated. <span>The electrons that are released at the anode flow through the wire, producing an electric current. Galvanic cells therefore transform chemical energy into electrical energy that can then be used to do work.</span>
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Convert 32.56 km/hr into ft/hr
Gekata [30.6K]
Note that
1 m = 3.2808 ft

Therefore
1 km = 3280.8 ft
and
32.56 \,  \frac{km}{h} = (32.56 \,  \frac{km}{h})*(3280.8 \,  \frac{ft}{km}) =  1.0682 \, \times 10^{5} \, \frac{ft}{h}

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3 years ago
If the K a Ka of a monoprotic weak acid is 7.3 × 10 − 6 , 7.3×10−6, what is the pH pH of a 0.40 M 0.40 M solution of this acid?
olga_2 [115]

Answer:

pH =3.8

Explanation:

Lets call the monoprotic weak acid HA, the dissociation equilibria in water will be:

HA + H₂O   ⇄ H₃O⁺ + A⁻    with  Ka = [ H₃O⁺] x [A⁻]/ [HA]

The pH is the negative log of the H₃O⁺ concentration, we know the equilibrium constant, Ka and the original acid concentration. So we will need to find the [H₃O⁺] to solve this question.

In order to do that lets set up the ICE table helper which accounts for the species at equilibrium:

                          HA                                   H₃O⁺                          A⁻          

Initial, M             0.40                                   0                              0

Change , M          -x                                     +x                            +x

Equilibrium, M    0.40 - x                              x                               x

Lets express these concentrations in terms of the equilibrium constant:

Ka = x² / (0.40 - x )

Now the equilibrium constant is so small ( very little dissociation of HA ) that is safe to approximate 0.40 - x to 0.40,

7.3 x 10⁻⁶ = x² / 0.40  ⇒ x = √( 7.3 x 10⁻⁶ x 0.40 ) = 1.71 x 10⁻³

[H₃O⁺] = 1.71 x 10⁻³

Indeed 1.71 x 10⁻³ is small compared to 0.40 (0.4 %). To be a good approximation our value should be less or equal to 5 %.

pH = - log ( 1.71 x 10⁻³ ) = 3.8

Note: when the aprroximation is greater than 5 % we will need to solve the resulting quadratic equation.

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