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Svetllana [295]
3 years ago
14

You notice something is growing in a 100ml pot of liquid soap. You take 1ml of this liquid soap and perform a serial dilution an

d plate to determine the number of bacteria per 1ml in the liquid soap. On the 1:100,000 dilution you plate out 1ml and get a count of 37 colonies. How many bacteria were present in 1ml of soap (cfu/1ml)?
Chemistry
1 answer:
andrew-mc [135]3 years ago
6 0

Answer:

3'700,000 cfu

Explanation:

One way to count the amount of bacteria in a medium is by doing a dilution of the sample and count how many colonies growth. Each colony is a cfu (Colony forming units).

In the problem, you count 37 colonies. The dilution was 1:100,000. That means the bacteria present in the soap is:

37 colonies × (100,000 / 1) = <em>3'700,000 cfu</em>

<em></em>

I hope it helps!

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What is the difference between bulk and particle scale? <br> Someone please help!!
sesenic [268]

Answer:

Particle density is the volumetric mass of the solid soil. It differs from bulk density because the volume used does not include pore spaces. Particle density represents the average density of all the minerals composing the soil.

Hope that helps

7 0
3 years ago
during a rising tide, ocean waves often become larger. if the amplitude of a wave increases by a factor of 1.1, by how much does
Sergio039 [100]

Answer:

1.21 times

Explanation:

The energy of a wave is proportional to the square of the amplitude of the wave.

Mathematically:

E\propto A^2

where

E is the energy of the wave

A is its amplitude

In this problem, the amplitude of the wave increases by a factor of 1.1; it means that the new amplitude can be written as

A'=1.1 A

Therefore, this means that the energy of the wave increases by a factor:

E'\propto A'^2=(1.1 A)^2 = 1.1^2 A^2 =1.21 A^2 = 1.21 E

Therefore, the energy of the wave increases by a factor 1.21.

8 0
3 years ago
For every pound a company spends on advertising, it spends £0,75 on its website. Express the
vodomira [7]
It will have a ratio of 4:3
6 0
3 years ago
How would you prepare 250 mL of a 0.100 M solution of fluoride ions<br> from solid CaF2?
andrey2020 [161]

In 250 mL of volumetric flask add 0.975875 grams of CaF_2 and dissolve it in the 250 mL of water.

Given:

The solid of calcium fluoride.

To prepare:

The 250 mL solution of 0.100 M of fluoride ions from solid calcium fluoride.

Method:

Molarity of the fluoride ion solution needed = M = 0.100 M

The volume of the fluoride ion solution needed = V = 250 mL

1 mL = 0.001L\\V=250 mL=250\times 0.001 L=0.250 L

The moles of fluoride ion needed = n

According to the definition of molarity:

M=\frac{n}{V}\\0.100M=\frac{n}{0.250 L}\\n=0.100M\times 0.250 L=0.025 mol

Moles of fluoride ion = 0.025 mol

We know that solid calcium fluoride dissolves in water to give calcium ions and fluoride ions.

CaF_2(s)\rightarrow Ca^{2+}(aq)+2F^-(aq)

According to reaction, 2 moles of fluoride ions are obtained from 1 mole of calcium fluoride, then 0.025 moles of fluoride ions will be obtained from:

=\frac{1}{2}\times 0.025 mol=0.0125 \text{mol of } CaF_2

Moles of calcium fluoride = 0.0125 mol

Mass of calcium fluoride needed to prepare the solution :

=0.0125 mol\times 78.07 g/mol=0.975875 g

Preparation:

  • Weight 0.975875 grams of calcium fluoride
  • Add weighed calcium fluoride to a volumetric flask of the labeled volume of 250 mL.
  • Now add a small amount of water to dissolve the calcium fluoride completely.
  • After this add more water up to the mark of the volumetric flask of volume 250 mL.

Learn more about molarity of solution ere:

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3 0
3 years ago
3 Points
svp [43]

Answer:

C. Splitting the atom

Explanation:

splitting the atom involves fission

4 0
3 years ago
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