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1 year ago

A 1-kohm resistor has a 15v across it. calculate power dissipation

Physics

1 answer:

enot [183]1 year ago

5 0

Given data

*The given resistor is R = 1 Kohm = 1 ×10^3 ohms

*The given voltage is V = 15 V

The formula for the power dissipation is given as

$P=\frac{V^2}{R}$

Substitute the known values in the above expression as

$\begin{gathered} P=\frac{(15)^2}{(1\times10^3)} \\ =0.225\text{ W} \end{gathered}$

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b) $\bigtriangledown T=1^{\circ}C.mile^{-1}$

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(a)

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