Question

a typical cmall flashlight contains two batteries each having na emf of 2.0 v connected in series with a bulb havin ga resistance of 16 ohms if the internal resistance of the batteries is negligible what power is delivered to the ublb

Answer 1

Answer:

P = 0.25 W

Explanation:

Given that,

The emf of the battry, E = 2 V

The resistance of a bulb, R = 16 ohms

We need to find the power delivered to the bulb. We know that, the formula for the power delivered is given by :

$P=\dfrac{V^2}{R}\\\\P=\dfrac{2^2}{16}\\\\=0.25\ W$

So, 0.25 W power is delivered to the bulb.