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Liono4ka [1.6K]
3 years ago
7

The drawing shows a laser beam shining on a plane mirror that is perpendicular to the floor. The angle of incidence is 33.0°. Th

e beam emerges from the laser at a point that is 1.10 m from the mirror and 1.80 m above the floor. After reflection, how far from the base of the mirror does the beam strike the floor?

Physics
1 answer:
valentina_108 [34]3 years ago
8 0

Answer:

x= 2.7734 m

Explanation:

Given the angle of incidence θ= 33.0°

distance from laser point and mirror = 1.10 m

laser point is 1.80 m above the floor

let the distance between mirror base and laser beam striking the floor after reflection = x  

figure has been attached and from the from the figure we can write

tan\theta= \frac{1.80}{x}

tan33\degree= \frac{1.80}{x}

tan33\degree= 0.649

putting value and solving we get

x= 2.7734 m

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Answer:

Force between two identical conducting ball will be 2.65\times 10^{-5}N                        

Explanation:

We have given there is two identical conducting small spheres having charge q_1=12nC=12\times 10^{-9}C and q_2=-21nC=-21\times 10^{-9}C

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A simple harmonic motion is defined by the amplitude and angular frequency of the oscillation, which are represented in the given function as 6 units and 98 rad/s respectively.

<h3>General wave equation for simple harmonic motion</h3>

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Learn more about simple harmonic motion here: brainly.com/question/17315536

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