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2 years ago

Which of the following halogens is darkest in colour?

Chemistry

1 answer:

Naddik [55]2 years ago

6 0

I₂ is the halogens which is darkest in colour than other.

<h3>What is halogen? </h3>

Halogens are the elements which belongs to group 17. Group 17 elements are known as halogens. They are highly electronegative in nature.

The last electronic configuration is ns2 np5. Since, one electron is less to get stable electronic configuration. Therefore, they accept one electron and get stable electronic configuration.

<h3>Why halogens are dark in colour? </h3>

As we move down the group, the darkness of colour increases. This is due to ionization energy which decreases as we move down the group. This is due to increase in the atomic size and decrease in nuclear form which further make high energy level to absorb lesser light and reflects deepen colour on moving down the group. Due to which they appears dark. Therefore, option A is the correct option.

Thus, we can concluded that I₂ is the halogens which is darkest in colour than other.

learn more about Halogens:

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Convert 0.64 moles of table salt (NaCl) to grams

Nana76 [90]

Answer:

0.64 moles of table salt = 37.44 grams of table salt

Explanation:

mNaCl = 0.64 x (23 + 35.5) = 37.44 grams

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3 years ago

Consider the mechanism. Step 1: A+B↽−−⇀CA+B↽−−⇀C equilibrium Step 2: C+A⟶DC+A⟶D slow Overall: 2A+B⟶D2A+B⟶D Determine the rate la

tatuchka [14]

Answer:

rate = k[A][B] where k = k₂K

Explanation:

Your mechanism is a slow step with a prior equilibrium:

$\begin{array}{rrcl}\text{Step 1}:& \text{A + B} & \xrightarrow [k_{-1}]{k_{1}} & \text{C}\\\text{Step 2}: & \text{C + A} & \xrightarrow [ ]{k_{2}} & \text{D}\\\text{Overall}: & \text{2A + B} & \longrightarrow \, & \text{D}\\\end{array}$

(The arrow in Step 1 should be equilibrium arrows).

1. Write the rate equations:

$-\dfrac{\text{d[A]}}{\text{d}t} = -\dfrac{\text{d[B]}}{\text{d}t} = -k_{1}[\text{A}][\text{B}] + k_{1}[\text{C}]\\\\\dfrac{\text{d[C]}}{\text{d}t} = k_{1}[\text{A}][\text{B}] - k_{2}[\text{C}]\\\\\dfrac{\text{d[D]}}{\text{d}t} = k_{2}[\text{C}]$

2. Derive the rate law

Assume k₋₁ ≫ k₂.

Then, in effect, we have an equilibrium that is only slightly disturbed by C slowly reacting to form D.

In an equilibrium, the forward and reverse rates are equal:

k₁[A][B] = k₋₁[C]

[C] = (k₁/k₋₁)[A][B] = K[A][B] (K is the equilibrium constant)

rate = d[D]/dt = k₂[C] = k₂K[A][B] = k[A][B]

The rate law is

rate = k[A][B] where k = k₂K

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4 years ago

Find the number of moles in 6120 ions of NaCl . Round your answer to two decimal places. Input your answer as 1.03E23, which is

FrozenT [24]

Answer:

Explanation:

NaCl = Na⁺ + Cl⁻

6120 ions of NaCl will contain 3060 ions of Na⁺ and 3060 ions of Cl⁻ , forming 3060 molecules of NaCl .

6.02 x 10²³ molecules of NaCl = 1 mole

3060 molecules of NaCl = 3060 x 10⁻²³ / 6.02 moles

= 508.30 x 10⁻²³ moles

= 5.08 x 10⁻²¹ moles

Answer : 5.08E-21 moles .

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