The reaction equilibrium is:
ClO⁻ + H₂O ⇄ HClO + OH⁻
Keq =
![\frac{[HClO][OH^{-} ]}{[ClO^{-} ]}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BHClO%5D%5BOH%5E%7B-%7D%20%5D%7D%7B%5BClO%5E%7B-%7D%20%5D%7D%20)
Answer:
Fig 3 is a mixture
Explanation:
Fig 1 has just one kind of atoms.
fig 2 shows 2 atoms of the same kind bonded together (compound)
fig 4 shows atoms of 2 different kinds bonded together (compound)
only in fig 3 we see uneven distribution of two kinds of atoms. By definition a mixture contains two or more kind of substances randomly arranged. So fig 3 shows arrangement of mixture
Answer B for Plato I just answer this question
corrected question:
A chemist determined by measurements that 0.03 moles of calcium sulfide participate in a chemical reaction. Calculate the mass of calcium sulfide that participates
Answer:
Explanation:
number of moles of CaS
molar mass of CaS = 40+32 = 72g/mol
number of moles = mass/ molar mass
mass = number of moles * molar mass
mass = 0.03 *72
mass of calcium sulfide = 2.16g
