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3 years ago

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Chemistry

1 answer:

kirill115 [55]3 years ago

4 0

Answer:

Number of moles of Fe = 10 mol

Number of moles of CO₂ = 15 mol

Explanation:

Given data:

Number of moles of iron oxide = 5 mol

Number of moles of carbon monoxide = 25 mol

Number of moles of product = ?

Solution:

Fe₂O₃ + 3CO → 2Fe + 3CO₂

Now we will compare the moles of reactant with product.

Fe₂O₃ : Fe

1 : 2

5 : 2×5 = 10 mol

Fe₂O₃ : CO₂

1 : 3

5 : 3×5 = 15 mol

CO : Fe

3 : 2

25 : 2/3×25 = 16.7 mol

CO : CO₂

3 : 3

25 : 25

Less number of moles of Fe and CO₂ are formed by iron oxide thus it will act as limiting reactant while CO is inn excess.

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QUESTION 8

MissTica

I think it’s noble gas NOT SURE

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3 years ago

Combustion of a 0.9835-g sample of a compound containing only carbon, hydrogen, and oxygen produced 1.900 g of co2 and 1.070 g o

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Find grams of C and H, using molar masses:
12.0 g C x (1.900 g CO2 / 44.0 g CO2) = 0.5182 grams C
2.02 g H x (1.070 g H2O /18 g H2O) = 0.1201 grams H

Since all the C and H in CO2 and H2O will come from the sample except oxygen, because we need to provide oxygen for sample to burn.

0.9835 g sample - 0.5182 g O - 0.1201 g H = 0.3452 grams O

find moles, using molar masses:
0.5182 grams C / 12.0 g/mol C = 0.0432 moles C
0.1201 grams H / 1.01 g/mol H = 0.119 moles H
0.3452 grams O / 16.0 g/mol O = 0.0216 moles O

0.0216 is lesser, so use it to normalize to find the ratio.
find ratios:
0.0432 moles C / 0.0216 = 2 moles C
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double the ration to eliminate decimals.

gives your answer is $C_4 H_{11} O_2$

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