What is the percent, by mass, of water in MgSO4.2H20

Chemistry

1 answer:

iris [78.8K]2 years ago

8 0

Answer:51.1%

Explanation:

Mass percent : It is defined as the mass of the given component present in the total mass of the compound. Formula used : First we have to calculate the mass of and . Mass of = 18 g/mole Mass of = 7 × 18 g/mole = 126 g/mole Mass of = 246.47 g/mole Now put all the given values in the above formula, we get the mass percent of in . Therefore, the mass percent of in is, 51.1%

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Answer:

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Explanation:

The change in Gibbs free energy of the reaction $\Delta G$ can be calculated using the formula.

$\Delta G = -RTlnK$

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T = the temperature of the reaction in Kelvin = (37.0 + 273) = 310K

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Therefore,

$\Delta G = -8.314 \times 310 \times ln (3.2) = -2997.83 kJ mol-1$

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Match each type of chemical bond with its properties. Drag the items

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Explanation:

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molecular compounds

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