A green rat snake that lives in the grass and a brown rat snake that lives in the desert is a form of geographically separated species.
Explanation:
The habitats of the green rat snake and brown rat snake shows that they are geographically separated species.
The two rat snakes are different species because of their distinct habitat and morphology.
When two species get separated by habitat their breeding method changes either by morphology or breeding pattern.
Such species do not produce viable offspring.
Thus a green rat snake and a brown rat snake have very different habitats they are now two different species.
Such species are said to be reproductively isolated species. Two species having genetic divergence undergo natural selection to adapt to the environment.
Answer:
Explanation:
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In this case, the molar enthalpy of reaction is obtained by dividing the involved energy by the reacting moles:
Thus, it is important to notice that the compound "uses" the energy, it means that it absorbs the energy, for that reason the sign is positive. Moreover, computing the result in kJ/mol we finally obtain:
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Answer:
pH = 1.32
Explanation:
H₂M + KOH ------------------------ HM⁻ + H₂O + K⁺
This problem involves a weak diprotic acid which we can solve by realizing they amount to buffer solutions. In the first deprotonation if all the acid is not consumed we will have an equilibrium of a wak acid and its weak conjugate base. Lets see:
So first calculate the moles reacted and produced:
n H₂M = 0.864 g/mol x 1 mol/ 116.072 g = 0.074 mol H₂M
54 mL x 1L / 1000 mL x 0. 0.276 moles/L = 0.015 mol KOH
it is clear that the maleic acid will not be completely consumed, hence treat it as an equilibrium problem of a buffer solution.
moles H₂M left = 0.074 - 0.015 = 0.059
moles HM⁻ produced = 0.015
Using the Henderson - Hasselbach equation to solve for pH:
ph = pKₐ + log ( HM⁻/ HA) = 1.92 + log ( 0.015 / 0.059) = 1.325
Notes: In the HH equation we used the moles of the species since the volume is the same and they will cancel out in the quotient.
For polyprotic acids the second or third deprotonation contribution to the pH when there is still unreacted acid ( Maleic in this case) unreacted.
Due to the variables that each inquiry has, Scientific inquiry follows a path of questioning and testing a hypothesis, however this changes in response to specific details.
Answer: PbCO
Explanation: its quite simple really, you need to get a periodic table and find the symbol of said elements. Lead is Pb, and carbonate is another word for carbon and oxygen, so it is C and O
