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Morgarella [4.7K]
3 years ago
12

Which of the following would release the most heat upon cooling from 75*C to 50*C?

Chemistry
2 answers:
Katyanochek1 [597]3 years ago
7 0

Answer:

A. 10g H2O (l)

On edge.nuity

Tresset [83]3 years ago
4 0
The answer should be 10g.
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What is the acceleration of the object’s motion? 0.5 m/s2 -0.5 m/s2 2 m/s2 -2 m/s2
djverab [1.8K]

Answer:  -2m/s2

Explanation:

Using the following equation ; acceleration = Change in velocity / time

i.e  a =  v - u / t

where  'a'  = acceleration

              v  = final velocity

              u  =  initial velocity

              t   =  time

Therefore;  from the graph we have acceleration to be, 0 - 6m/s / 3s  = -2m/s2

5 0
3 years ago
Which of the following "spheres" is NOT involved in the water cycle?
olya-2409 [2.1K]
B is the correct answer.
The exosphere is the outermost region of the atmosphere the gradually merges out into space. The water cycle does not occur within this region.
5 0
3 years ago
Read 2 more answers
How do we get energy from the food we eat?
expeople1 [14]

Answer:

A

Explanation:

I used my resources and they was explaining and I came to a resolution that it was A

5 0
2 years ago
A certain orbital of the hydrogen atom has n = 4 and l = 2 what are the possible values of ml for this orbital?
Nadya [2.5K]

The ml is also called as the magnetic quantum number. The value of ml can range from –l to +l including zero. Hence all of the possible values for ml given that l = 2 are:

<span>-2, -1, 0, + 1, + 2</span>

3 0
3 years ago
Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r
denis23 [38]

Answer :

(1) The frequency of photon is, 3\times 10^{10}Hz

(2) The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

Explanation : Given,

Wavelength of photon = 1.0cm=0.01m     (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of photon

\lambda = wavelength of photon

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

\nu=\frac{3\times 10^8m/s}{0.01m}

\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz    (1Hz=1s^{-1})

The frequency of photon is, 3\times 10^{10}Hz

(2) Now we have to calculate the energy of photon.

Formula used :

E=h\times \nu

where,

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})

E=1.988\times 10^{-23}J/photon

The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) Now we have to calculate the energy in J/mol.

E=1.988\times 10^{-23}J/photon

E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)

E=11.97J/mol

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

3 0
3 years ago
Read 2 more answers
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