Question

losing my marbles: i have a bag containing 100 marbles, 99 of which are blue, and one of which is green. how many marbles must i remove (checking their color before removing them) so that the the probability a randomly drawn marble is green is 2%?

Answer 1

The probability that a green marble is randomly drawn will be 2% if 50 blue marbles are removed. The probability of randomly picking a green marble will be greater if there are fewer marbles.

The probability of an event can be expressed as

P(A) = n(A) / n(S)

Where

• P(A) = 2% = 0,02
• n(A) = 1 (number of green marble)

We must find the value of n(S) (the total number of marbles) so that we know how many marbles that must be removed.

• P(A) = n(A) / n(S)
• 0,02 = 1 / n(S)
• n(S) = 50

Hence, the probability of randomly drawn green marble will be 2% if there are 50 marbles. So, 50 blue marbles should be removed.

Leaen more about probability at brainly.com/question/29350527

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