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snow_tiger [21]
1 year ago
6

Hello! Is it possible you can solve this chemistry question?

Chemistry
1 answer:
Pavlova-9 [17]1 year ago
6 0

Answer:

a. Gas pressure: decreases

b. Gas moles: remain constant

c. Average speed of gas molecules: decreases

d. Average distance between molecules: large

Explanation:

The kinetic molecular theory of gases explains the behavior and properties of gases.

In this case, the gas is cooled, so its temperature decreases.

a. Gas pressure:

To analyze the gas pressure we can use the Ideal Gas formula P.V=n.R.T, where pressure and temperature are directly proportional, that is, if the temperature decreases, the gas pressure will also decrease.

b. Gas moles:

The moles of gas remain constant, since the flask is sealed, so gases cannot enter or leave the flask.

c. Average speed of gas molecules:

Temperature is related to the average speed of movement of molecules, so as temperature decreases, the average speed of molecules also decreases.

d. Average distance between molecules:

As the average speed of molecules decreases, they stay in place, hardly moving, so the average distance between molecules is greater than if the molecules were moving faster.

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Answer: The final temperature of nickel and water is  25.2^{o}C.

Explanation:

The given data is as follows.

   Mass of water, m = 55.0 g,

  Initial temp, (t_{i}) = 23^{o}C,      

  Final temp, (t_{f}) = ?,

  Specific heat of water = 4.184 J/g^{o}C,      

Now, we will calculate the heat energy as follows.

           q = mS \Delta t

              = 55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)

Also,

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   Final temperature, t_{f} = ?

 Specific heat of nickel = 0.444 J/g^{o}C

Hence, we will calculate the heat energy as follows.

          q = mS \Delta t

             = 15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)      

Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

              q_{water}(gain) = -q_{alloy}(lost)

55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C) = -(15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C))

       t_{f} = \frac{25.9^{o}C}{1.029}

                 = 25.2^{o}C

Thus, we can conclude that the final temperature of nickel and water is  25.2^{o}C.

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How many grams of hydrogen are necessary to react with 2.85 mol CO
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2.85 mol Co x (2mol H2/1 mol Co)=5.70 mol just concert to grams

5.70 mol H2 x (2 g H2/1 mol H2) =11.40 grams of H2

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Answer:

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Due to its low freezing point, it can still function effectively as a thermometric liquid, expanding and contracting properly based on the applied heat,  when dealing with temperature measurements that are at about -38.2°F.

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