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siniylev [52]
3 years ago
6

A car is held motionless off the ground by a hovering helicopter. If the car's mass is 1500kg, what is the force on the car due

to gravity? A. 153 N B. 1470 N C. 1500 N D. 14,700 N
Chemistry
2 answers:
aleksandr82 [10.1K]3 years ago
7 0

Answer:

option D

Explanation:

In this case, we have a helicopter lifting a car. The car has a mass of 1500 kg and we want to know the force that the car is feeling due to gravity.

In this case, as the car is being lifted by the helicopter, we can say that the force of the helicopter is equivalent to the force of gravity that the car is feeling.

Using the second law of Newton we have:

F = m.a

In this case, the force that gravity exerts, is the weight and is calculated with the same expression but using the gravity acceleration of Earth whic is 9.81 m/s², therefore:

W = m.g

Now that we have mass and gravity, we can calculate the force of gravity so:

W = 1500 * 9.81

W = 14,715 N

This is close to the value of option D, so the answer would be that.

bixtya [17]3 years ago
6 0

<span>Force of the helicopter is equivalent to weight for this case. </span>Weight is calculated by multiplying the mass of the object and the acceleration. For this case, the acceleration would be the acceleration due to gravity which is equal to 9.81 m/s^2. We calculate as follows:<span>

W = mg 
<span>W = 1500 kg ( 9.81 m/s^2 )</span></span>

<span><span>W = 14715 N </span></span>

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Answer:

The partial pressure of acetic acid is 73.5 torr

Explanation:

Step 1: Data given

Total pressure is 226 torr

mass of acetic acid = 126 grams

mass of methanol = 141 grams

 

Step 2: Calculate moles of acetic acid

moles acetic acid = mass acetic acid / molar mass acetic acid

moles acetic acid = 127 grams / 60.05 g/mol

moles acetic acid = 2.115 moles

Step 3: Calculate moles of methanol

moles methanol = 141 grams / 32.04 g/mol

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Step 4: Calculate total moles

Total moles = moles of acetic acid + moles methanol

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Step 5: Calculate mole fraction of acetic acid

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Step 6: Calculate partial pressure of acetic acid

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We can control this by calculating the partial pressure of methanol

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