<span>Without friction, there will be undamped simple harmonic motion. The force of the spring is proportional to the distance from the equilibrium point. The period of oscillation will be independent of the amplitude.
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Answer:
200 mL
Explanation:
Given that,
Initial volume, V₁ = 300 mL
Initial pressure, P₁ = 0.5 kPa
Final pressure, P₂ = 0.75 kPa
We need to find the final volume of the sample if pressure is increased at constant temperature. It is based on Boyle's law. Its mathematical form is given by :

V₂ is the final volume

So, the final volume of the sample is 200 mL.
The amount of power change if less work is done in more time"then the amount of power will decrease".
<u>Option: B</u>
<u>Explanation:</u>
The rate of performing any work or activity by transferring amount of energy per unit time is understood as power. The unit of power is watt
Here this equation showcase that power is directly proportional to the work but dependent upon time as time is inversely proportional to the power i.e as time increases power decreases and vice versa.
This can be understood from an instance, on moving a load up a flight of stairs, the similar amount of work is done, no matter how heavy but when the work is done in a shorter period of time more power is required.
Answer:
The correct answer is V√5
Explanation:
Let V be the velocity of the satellite orbiting at radius r.
Let V(5r) be the velocity of the satellite orbiting at radius 5r.
Recall:
Escape velocity is given by:
V = √(2gr)
Where V is the escape velocity
g is the acceleration due to gravity
r is the radius of the earth.
With the above equation, we can obtain the answer to the question as follow:
V = √(2gr)
V(5r) = √(2g5r)
Next, we'll obtained the ratio of V(5r) to V as shown below
V(5r) : V => V(5r)/V
V(5r)/V = √(2g5r) / √(2gr)
V(5r)/V = √5
Cross multiply
V(5r) = V√5
From the above illustration, we can see that when the satellite is moved to 3r, then the expression for the velocity will be V√5