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Gnoma [55]
3 years ago
14

A 2.0-Coulomb bead is given 20 Joules of electric potential energy by lifting it from the "ground" to point A. If a second bead

with twice as much charge, 4.0 Coulombs, is lifted through the same distance, intuitively, how much electric potential energy do you expect it to have at point A?
Physics
1 answer:
Katen [24]3 years ago
4 0

Answer:

40 J

Explanation:

c_1 = 4 C

c_2 = 2 C

U_1 = 20 J

The potential energy is directly proportional to the charge of the particle

U\propto c

\dfrac{U_2}{U_1}=\dfrac{c_2}{c_1}\\\Rightarrow U_2=\dfrac{U_1c_2}{c_1}\\\Rightarrow U_2=\dfrac{20\times 4}{2}\\\Rightarrow U_2=40\ J

The potential energy expected is 40 J

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A car accelerates uniformly from rest and
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Answer:

29.75 revolutions

Explanation:

The kinematic formula for distance, given a uniform acceleration a and an initial velocity v₀, is

d=v_0t+\frac{1}{2}at^2

This car is starting from rest, so v₀ = 0 m/s. Additionally, we have a = 9.2/9.7 m/s² and t = 9.7 s. Plugging these values into our equation:

d=0t+\frac{1}{2}\left(\frac{9.2}{9.7}\right)(9.7)^2\\d=\frac{1}{2}(9.2)(9.7)\\d=4.6(9.7)\\d=44.62

So, the car has travelled 44.62 m in 9.7 seconds - we want to know how many of the tire's <em>circumferences</em> fit into that distance, so we'll first have to calculate that circumference. The formula for the circumference of a circle given its diameter is c=\pi{d}, which in this case is 47.8π cm, or, using π ≈ 3.14, 47.8(3.14) = 150.092 cm.

Before we divide the distance travelled by the circumference, we need to make sure we're using the same units. 1 m = 100 cm, so 105.092 cm ≈ 1.5 m. Dividing 44.62 m by this value, we find the number of revs is

44.62/1.5\approx29.75 revolutions

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