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Gnoma [55]
2 years ago
14

A 2.0-Coulomb bead is given 20 Joules of electric potential energy by lifting it from the "ground" to point A. If a second bead

with twice as much charge, 4.0 Coulombs, is lifted through the same distance, intuitively, how much electric potential energy do you expect it to have at point A?
Physics
1 answer:
Katen [24]2 years ago
4 0

Answer:

40 J

Explanation:

c_1 = 4 C

c_2 = 2 C

U_1 = 20 J

The potential energy is directly proportional to the charge of the particle

U\propto c

\dfrac{U_2}{U_1}=\dfrac{c_2}{c_1}\\\Rightarrow U_2=\dfrac{U_1c_2}{c_1}\\\Rightarrow U_2=\dfrac{20\times 4}{2}\\\Rightarrow U_2=40\ J

The potential energy expected is 40 J

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Answer:

Pt 1: W=39J

Pt 2: θ = 19.7

Explanation:

Part 1:

W=FS

W=F_{_xs_x}+F{_ys_y}

imagine the "i"and the "j" with the hat

W=(10i-1j)(4i+3j)

W=(10*4)-(1*1)

W=40-1

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Part 2:

|F|=\sqrt{10^2+(-1)^2}

|F|=\sqrt{101}

|S|=\sqrt{4^2+1^2}

|S|=\sqrt{17}

W=|F||S|cosθ

39=(\sqrt{101})(\sqrt{17} )cosθ

θ = 19.7

Hope it helps

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