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rusak2 [61]
3 years ago
8

Name the missing force... Normal    Spring    Tension    Air Resistance

Physics
1 answer:
Kay [80]3 years ago
4 0

the missing force is spring force.

The object is hanging from the spring and the spring is stretched by some distance from its equilibrium position.  due to this stretch in the spring , a spring force starts acting on the object trying to regain its equilibrium position.

the spring force is given as

F = kx

where F = spring force ,k = spring constant , x = stretch in the spring.

the spring force balances the weight of the object in down direction and hence keeps the block from falling down.

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Work output of a large machine in a factory is 89,000 joules, and it’s input is 102,000 joules. Work output of a similar machine
mojhsa [17]
(89000/102000)×100
=87.25%

(92000/104000)×100
=88.46%

efficiency is (output/input)×100
if u get confused which way input and output should go, remember the smaller value is always output and it's above in the fraction, then only it's possible to get a efficiency lower than 100.

7 0
2 years ago
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Theo mixes cake batter and places it in the oven at 350°F for 45 minutes. Explain what type of reaction baking a cake represents
Nataly_w [17]

Baking a cake creates a endothermic reaction. When heated, the baking soda/powder reacts, the eggs change form, and everything else follows suit. The baking soda/powder creates the rising of the cake.

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3 years ago
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What is the meaning of the safety symbol shown below?
lora16 [44]

Answer:

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Explanation:

8 0
2 years ago
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(a) Find the frequency of revolution of an electron with an energy of 114 eV in a uniform magnetic field of magnitude 46.7 µT. (
stira [4]

Answer:

(a)  1.3 x 10^6 Hz

(b) 76.73 cm

Explanation:

(a)

the formula for the frequency is given by

f = B q / 2 π m

where, B be the strength of magnetic field, q be the charge on one electron, m is the mass of one electron.

B = 46.7 micro tesla = 46.7 x 10^-6 T

q = 1.6 x 10^-19 C

m = 9.1 x 10^-31 kg

f = (46.7 x 10^-6 x 1.6 x 10^-19) / (2 x 3.14 x 9.1 x 10^-31) = 1.3 x 10^6 Hz

(b) K = 114 eV = 114 x 1.6 x 10^-19 J = 182.4 x 10^-19 J

K = 1/2 mv^2

182.4 x 10^-19 = 0.5 x 9.1 x 10^-31 x v^2

v = 6.3 x 10^6 m/s

r = m v / B q

Where, r be the radius of circular path

r = (9.1 x 10^-31 x 6.3 x 10^6) / (46.7 x 10^-6 x 1.6 x 10^-19)

r = 0.7673 m = 76.73 cm  

5 0
3 years ago
The concept of critical density is just like the idea of escape velocity for a projectile launched from the earth. An object lau
ikadub [295]

Answer:

v = √ 2 G M/ R_{e}

Explanation:

To find the escape velocity we can use the concept of mechanical energy, where the initial point is the surface of the earth and the end point is at the maximum distance from the projectile to the Earth.

Initial

        Em₀ = K + U₀

Final

        Em_{f} =  U_{f}

The kinetic energy is k = ½ m v²

The gravitational potential energy is U = - G m M / r

r is the distance measured from the center of the Earth

How energy is conserved

       Em₀ =  Em_{f}

       ½ mv² - GmM / R_{e} = -GmM / r

       v² = 2 G M (1 /  R_{e} – 1 / r)

       v = √ 2GM (1 / R_{e} – 1 / r)

The escape velocity is that necessary to take the rocket to an infinite distance (r = ∞), whereby 1 /∞ = 0

        v = √ 2GM /  R_{e}

5 0
2 years ago
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