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rusak2 [61]
4 years ago
8

Name the missing force... Normal    Spring    Tension    Air Resistance

Physics
1 answer:
Kay [80]4 years ago
4 0

the missing force is spring force.

The object is hanging from the spring and the spring is stretched by some distance from its equilibrium position.  due to this stretch in the spring , a spring force starts acting on the object trying to regain its equilibrium position.

the spring force is given as

F = kx

where F = spring force ,k = spring constant , x = stretch in the spring.

the spring force balances the weight of the object in down direction and hence keeps the block from falling down.

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What is the 4 digit code
Contact [7]

Answer:

lol doge meme

Explanation:

8 0
3 years ago
Sometimes, I have to take my cat, Gigi, in the car. She doesn’t like this, and tends to hide under the couch when she knows she
Reika [66]

Answer:

F - fr = ma ,    N - W = 0

Explanation:

In this exercise we are asked to identify the forces that act on the jack, for this we will use Newton's second law

On the x axis

We have two forces: the friction and the force of the girl who pulls the cat

           F - fr = ma

On the y axis

There are two forces: normal and weight

         N - W = 0

A diagram of these forces can be seen in the attachment

8 0
3 years ago
The cost, density and resistivity of copper, steel and aluminum
otez555 [7]
Density of copper: 8,9
Density of steel: 7,7
Density of aluminum: 2,7
And
Resistivity of copper: 1,7
Resistivity of steel: 16,9
Resistivity of aluminum: <span>2,7</span>

Hope I Helped You!!! :-)

Have A Good Day!!!
3 0
3 years ago
Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of -0.9537 N when separated by
scoray [572]

Answer:

<em>The initial charges on the spheres are  </em>6.796\ 10^{-6}\ c and -3.898\ 10^{-6}\ c

Explanation:

<u>Electrostatic Force </u>

Two charges q1 and q2 separated a distance d exert a force on each other which magnitude is computed by the known Coulomb's formula

\displaystyle F=\frac{K\ q_1\ q_2}{d^2}

We are given the distance between two unknown charges d=50 cm = 0.5 m and the attractive force of -0.9537 N. This means both charges are opposite signs.

With these conditions we set the equation

\displaystyle F_1=\frac{K\ q_1\ q_2}{0.5^2}=-0.9537

Rearranging

\displaystyle q_1\ q_2=\frac{-0.9537(0.5)^2}{k}

Solving for q1.q2

\displaystyle q_1\ q_2=-2.6492.10^{-11}\ c^2\ \ ......[1]

The second part of the problem states the spheres are later connected by a conducting wire which is removed, and then, the spheres repel each other with an electrostatic force of 0.0756 N.

The conducting wire makes the charges on both spheres to balance, i.e. free electrons of the negative charge pass to the positive charge and they finally have the same charge:

\displaystyle q=\frac{q_1+q_2}{2}

Using this second condition:

\displaystyle F_2=\frac{K\ q^2}{0.5^2}=\frac{K(q_1+q_2)^2}{(4)0.5^2}=0.0756

\displaystyle q_1+q_2=2.8983\ 10^{-6}\ C

Solving for q2

\displaystyle q_2=2.8983\ 10^{-6}\ C-q_1

Replacing in [1]

\displaystyle q_1(2.8983\ 10^{-6}-q_1)=-2.64917.10^{-11}

Rearranging, we have a second-degree equation for q1.  

\displaystyle q_1^2-2.8983.10^{-6}q_1-2.64917.10^{-11}=0

Solving, we have two possible solutions

\displaystyle q_1=6,796.10^{-6}\ c

\displaystyle q_1=-3.898.10^{-6}\ c

Which yields to two solutions for q2

\displaystyle q_2=-3.898.10^{-6}\ c

\displaystyle q_2=6.796.10^{-6}\ c

Regardless of their order, the initial charges on the spheres are 6.796\ 10^{-6}\ c and -3.898\ 10^{-6}\ c

8 0
3 years ago
He amount of current flowing in a circuit can be measured by
Papessa [141]

First question:
The magnitude of current flowing in a circuit is described in
units of Amperes.  The device used to measure it is an Ampmeter,
or Ammeter.

Second question:
This question is so absurd that it should not be dignified with an
answer.  Although 'E' is often used as the symbol for Electromotive
force, potential difference, and voltage, there's certainly no rule. 
Anyone is free to use  'M',  'Q',  'Θ', or  'Щ' to denote voltage when
they write electrical formulas, just as long as they make sure to
explain the meaning of whatever symbols they use.

7 0
4 years ago
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