Name the missing force... Normal Spring Tension Air Resistance

Physics

1 answer:

Kay [80]3 years ago

4 0

the missing force is spring force.

The object is hanging from the spring and the spring is stretched by some distance from its equilibrium position. due to this stretch in the spring , a spring force starts acting on the object trying to regain its equilibrium position.

the spring force is given as

F = kx

where F = spring force ,k = spring constant , x = stretch in the spring.

the spring force balances the weight of the object in down direction and hence keeps the block from falling down.

You might be interested in

A solid cylinder of mass 10 kg is pivoted about a frictionless axis thought the center O. A rope wrapped around the outer radius

taurus [48]

Torque acting dowward = 6 x 0.5 = 3 Nm

Torque acting to the right = 5 x 1 = 5 Nm

5 - 3 = 2 Nm

inertia = 1/2 mr^2

0.5 x 10 x 1^2 = 5 kg-m^2
2/5 = alpha = 0.4 rad /s^2

Hope this helps

5 0

3 years ago

Read 2 more answers

What is the function of the electron transport chain in cellular respiration. why is oxygen needed for the electron transport ch

SpyIntel [72]

1) <span>The function of the electron transport chain is to pump protons in the mitochondrion inter-membrane, thus building up a proton gradient. This gradient will allow the ATP syntheses</span><span>.</span>

2) Why we need oxygen for the electron transport chain:
At the end of the electron transport chain is the Oxygen that will accept electrons and picks up protons to form water. If the oxygen molecule is not there the electron transport chain will stop running, and ATP will no longer be produced. Basically, we need the oxygen to produce more ATP.

8 0

3 years ago

How will the boat be affected if it enters a part of the river where the current is moving south at 2 m/s?

Paladinen [302]

Answer:

the boat will either break or go alot faster

Explanation:

3 0

3 years ago

Read 2 more answers

An electron in the n = 7 level of the hydrogen atom relaxes to a lower energy level, emitting light of 397 nm. what is the value

Dimas [21]

Answer:

$n_f=2$

Explanation:

It is given that,

Initially, the electron is in n = 7 energy level. When it relaxes to a lower energy level, emitting light of 397 nm. We need to find the value of n for the level to which the electron relaxed. It can be calculate using the formula as :

$\dfrac{1}{\lambda}=R(\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2})$