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4 years ago

A change in velocity means a change in?

Physics

2 answers:

Anon25 [30]4 years ago

8 0

Velocity can be changed in many ways. it can slow down, speed up, or change direction

Scorpion4ik [409]4 years ago

4 0

An object can change velocity in a number of ways: it can slow down, it can speed up, or it can change direction. A change in speed, or a change in direction, or a change in both speed and direction means that the object has a change in velocity.

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If a car with a mass of 1,200 kg traveling westward at 30 m/s is

forsale [732]

The net force acting on the car is equal to -12000 Newton.

<u>Given the following data:</u>

Mass = 1,200 kg

Initial velocity = 30 m/s.

Final velocity = 0 m/s (since the car came to a stop).

Time = 3 seconds.

To determine the net force acting on the car:

<h3>How to calculate the net force.</h3>

Mathematically, the net force acting on the car is given by Newton's Second Law of Motion:

$F = \frac{m(v\;-\;u)}{t}$

<u>Where:</u>

m is the mass.

t is the time.

u is the initial velocity.

u is the final velocity.

Substituting the given parameters into the formula, we have;

$F = \frac{1200 \times (0\;-\;30)}{3}\\\\F = \frac{1200 \times (-30)}{3}\\\\F = \frac{-36000 }{3}$

Net force = -12000 Newton.

Read more on net force here: brainly.com/question/1121817

5 0

2 years ago

All systems have what

Korvikt [17]

Number 3 is the naswer

6 0

4 years ago

Can you build up a resistance to motion sickness

yarga [219]

Not that I know of. Sometimes watching something, listening to music, reading a book, or talking can help. There are some homeopathic remedies that can help as well.

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3 years ago

A SPARK PLUG IN AN AUTOMOBILE ENGINE CONSISTS OF TWO

kirill [66]

Answer:

Electric potential, $V=3.52\times 10^{12}\ volts$

Explanation:

It is given that,

The magnitude of electric field, $E=4.7\times 10^7\ V/m$

Distance between automobile engines that consists of metal conductors, $d = 0.75\ mm = 7.5\times 10^4\ m$

Let V is the magnitude of the potential difference between the conductors. The relation between the electric field and the electric potential is given by:

$V=E\times d$