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Likurg_2 [28]
3 years ago
9

When a predator population increases what happens to the prey population? Increase Decrease Dies Stays the same

Chemistry
1 answer:
AnnyKZ [126]3 years ago
8 0

Answer: as the number of predators increases, more prey are captured. as a result the prey population starts to decrease.

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Determine the mole fractions and partial pressures of CO2, CH4, and He in a sample of gas that contains 1.20 moles of CO2, 1.79
BARSIC [14]

Answer :  The mole fraction and partial pressure of CH_4,CO_2 and He gases are, 0.267, 0.179, 0.554 and 1.54, 1.03 and 3.20 atm respectively.

Explanation : Given,

Moles of CH_4 = 1.79 mole

Moles of CO_2 = 1.20 mole

Moles of He = 3.71 mole

Now we have to calculate the mole fraction of CH_4,CO_2 and He gases.

\text{Mole fraction of }CH_4=\frac{\text{Moles of }CH_4}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }CH_4=\frac{1.79}{1.79+1.20+3.71}=0.267

and,

\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }CO_2=\frac{1.20}{1.79+1.20+3.71}=0.179

and,

\text{Mole fraction of }He=\frac{\text{Moles of }He}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }He=\frac{3.71}{1.79+1.20+3.71}=0.554

Thus, the mole fraction of CH_4,CO_2 and He gases are, 0.267, 0.179 and 0.554 respectively.

Now we have to calculate the partial pressure of CH_4,CO_2 and He gases.

According to the Raoult's law,

p_i=X_i\times p_T

where,

p_i = partial pressure of gas

p_T = total pressure of gas  = 5.78 atm

X_i = mole fraction of gas

p_{CH_4}=X_{CH_4}\times p_T

p_{CH_4}=0.267\times 5.78atm=1.54atm

and,

p_{CO_2}=X_{CO_2}\times p_T

p_{CO_2}=0.179\times 5.78atm=1.03atm

and,

p_{He}=X_{He}\times p_T

p_{He}=0.554\times 5.78atm=3.20atm

Thus, the partial pressure of CH_4,CO_2 and He gases are, 1.54, 1.03 and 3.20 atm respectively.

4 0
3 years ago
Elements are arranged in groups by similar atomic structure on the periodic table. This allows for an element's properties to be
svlad2 [7]

D) energy required to remove a valence electron

Explanation:

The ionization energy is the energy required to remove a valence electron from an element.

Different kinds of atoms bind their valence electrons with different amount of energy.

  • To remove the electrons, energy must be supplied to the atom.
  • The amount of energy required to remove the an electron in the valence shell is the ionization energy or ionization potential.
  • The first ionization energy is the energy needed to remove the most loosely bound electron in an atom in the ground state.
  • The ionization energy measures the readiness of an atom to loose electrons.

Learn more:

Ionization energy brainly.com/question/5880605

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What is the result at the end of meiosis II?
VMariaS [17]

Answer:

B.) two diploid cells

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Sodium chloride is a _________ in this reaction: sodium chlorate → sodium chloride + oxygen
Murrr4er [49]
The most obvious answer for this would be a product i think.
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When an electron drops from a higher energy level to a lower one, energy is emitted. in comparison, how much energy is required
NNADVOKAT [17]

Energy is released when an electron transitions from one energy level to another. In contrast, the same amount of energy is needed to carry out the process, the other way around, from the bottom elevation to the upper one.

What occurs when an electron transitions from one energy level to another?

  • The energy of the electron drops when it changes levels, and the atom releases photons. The electron emits a photon when it transitions from a greater to a lower energy level. The energy emitted is precisely the energy that is lost when an electron moves to a level with less energy.
  • An atom's electrons have negative energy. The electron must be given energy in order to be removed from the hydrogen atom, as shown by the negative sign. The quantity of energy in the atom will rise by supplying the electron with energy. Similar to how a ball on Earth chooses to rest in valleys rather than hills, the electron wants to spend the majority of its time at a lower energy level.
  • For a brief period of time, the electron remains in an excited state. The energy required to bring the electron to its lower-energy state will be released when the electron transitions between excited and unexcited states.

Learn more about electrons here:

brainly.com/question/1255220

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1 year ago
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