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gogolik [260]
3 years ago
7

In Hooke's law, Fspring=kΔx, what does the ∆x stand for?

Chemistry
2 answers:
KonstantinChe [14]3 years ago
7 0

Answer:

Explthe distance the spring stretchesanation:

Levart [38]3 years ago
3 0

Answer:

"The distance the spring stretches " is the correct option.

Explanation:

The Hooke's law for a spring is given by :

F_{spring}=-k\Delta x

Where

k is spring constant in N/m

\Delta x is the compression or stretching in the spring

Hence, the correct option for \Delta x is (b) "the distance the spring stretches .

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For this problem we can use half-life formula and radioactive decay formula.

Half-life formula,
t1/2 = ln 2 / λ

where, t1/2 is half-life and λ is radioactive decay constant.
t1/2 = 8.04 days

Hence,         
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Radioactive decay law,
Nt = No e∧(-λt)

where, Nt is amount of compound at t time, No is amount of compound at  t = 0 time, t is time taken to decay and λ is radioactive decay constant.

Nt = ?
No = 1.53 mg
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t    = 13.0 days 

By substituting,
Nt = 1.53 mg e∧((-0.693/8.04 days) x 13.0 days))
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Hence, mass of remaining sample after 13.0 days = 0.499 mg

The answer is "e"

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Explanation: pls give brainliest thanks!

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