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frozen [14]
1 year ago
7

A motorcycle traveling at 25 m/s accelerates at a rate of 6 m/s2 for 4 seconds. What is the final speed of the motorcycle in m/s

?
Physics
1 answer:
givi [52]1 year ago
8 0

Initial velocity = Vo= 25 m/s

Final velocity = V = x

Acceleration= a = 6 m/s^2

time= t = 4 seconds

Appy the equation:

V = Vo + at

Replacing:

V = 25 + 6(4) = 25 + 24 = 49 m/s

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Based on Hooke's law, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.

<h3>What is the spring constant?</h3>

The spring constant or stiffness constant of an elastic spring is constant which describes the extent a bit forceapplied to an elastic spring will extend it.

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Assuming, a body's muscle mechanism is a spring obeying Hooke's law, the effective mass of the spring with mass m is 1/3 of the mass of the spring = m/3

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where K is spring constant and e is the extension produced.

Therefore, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.

Learn more about Hooke's law at: brainly.com/question/12253978

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