Answer:
True, check attachment for code
Explanation:
To convert java strings of text to upper or lower case, we can use and inbuilt methods To Uppercase and To lower case.
The first two lines of code will set up a String variable to hold the text "text to change", and then we print it out.
The third line sets of a second String variable called result.
The fourth line is where the conversion is done.
We can compare the string
We can compare one string to another. (When comparing, Java will use the hexadecimal values rather than the letters themselves.) For example, if we wanted to compare the word "Fat" with the word "App" to see which should come first, you can use an inbuilt string method called compareTo.
Check attachment for the code
<span>So we want to know when do we have enough information about the atom that we can say that it is electrically neutral. So the information we need to know is the number of protons, whic are positively charged particles and the number of electrons which are negatively charged particles. Number of protons has to be equal to number of electrons for the atom to have neutral charge. Neutrons are electrically neutral so their number doesn't change the charge of the atom. So the correct answer is B. </span>
Answer:
r = 3519.55 m
Explanation:
We know that the acceleration of a particle in a circular motion is directed towards the center of the circumference and has magnitude:
F = rω^2
Where r is the radius of the circumference and ω is the angular velocity.
From the two acceleration vectors we find that their magnitude is
√(7^2+6^2) = √85
Therefore:
√85 m/s^2= rω^2
Now we need to calculate the angular velocity to obtain the radius. Since t2-t1 = 3s is less than one period we can be sure that the angular velocity is equals to the angle traveled between this time divided by 3 s.
The angle with respect to the x-axis for the particle at t1 and t2 is:
Therefore, the angular velocity ω is (in radians per second):
Therefore:
r = √85 / (0.0511813)^2 = 3519.55 m
Dark matter has been detected by its gravitational pull.