Question

A 100-n force has a horizontal component of 80 n and a vertical component of 60 n. the force is applied to a box which rests on a level frictionless floor. the cart starts from rest, and moves 2.0 m horizontally along the floor. what is the cart's final kinetic energy?

Answer 1

160 Joules

   For this problem, we can ignore the vertical component of the applied force and focus on only the horizontal component of 80 N and since work is defined as force over distance, let's multiply the force by the distance: 80 N * 2.0 m = 160 Nm = 160 kg*m^2/s^2 = 160 Joules.

   So the cart has a final kinetic energy of 160 Joules.