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Dmitrij [34]
3 years ago
7

How much work is done using a 500 W microwave for 5 minutes

Physics
1 answer:
frosja888 [35]3 years ago
6 0

Power = work done/time

work done = power x time

                  = 500x5x60

                  = 150000J

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The Earth orbits around the sun because the gravitational force that the sun
kotykmax [81]
<h3>Question -:</h3>

The Earth orbits around the sun because the gravitational force that the sun

exerts on the Earth:

O A. causes Earth's acceleration toward the sun.

O B. is very small because the sun is so far from the Earth.

O c. is smaller than the force the Earth exerts on the sun.

O D. pushes the Earth away from the sun.

<h3>Answer -:</h3>

O A. causes Earth's acceleration toward the sun.

<em>I </em><em>hope </em><em>this</em><em> </em><em>helps</em><em>,</em><em> </em><em>have </em><em>a </em><em>nice </em><em>time </em><em>ahead!</em>

5 0
2 years ago
Can someone help me? Idk why I can't understand this
olya-2409 [2.1K]
It's been a while since I've studied this, but my answers would be:

13. 5730 years. The half-life of a substance is the amount of time it takes for half of it to decay, and, according to the graph, half of the substance remained at 5730 years.

14. 10740 years. According to the graph, only 25% of the carbon remained after 10740 years.

15. 15 atoms. According to the graph, only 12.5% of the carbon remained after 16110 years. 12.5% of 120 atoms is 15 atoms.

16. 1600 atoms. According to the graph, if a sample of carbon is 10740 years old, only 25% of it remains. To find the original amount, multiply the current amount by (100% / 25%), which equals 4. So, 4. 400 atoms * 4 = 1600 atoms is the original amount.
5 0
3 years ago
A circle has an initial radius of 50ft when the radius begins decreasing at a rate of 2ft/s. what is the rate of change of the a
valkas [14]
The area of the circle with radius r is
A = πr²

The rate of change of area with respect to time is
\frac{dA}{dt} = \frac{dA}{dr} . \frac{dr}{dt} =2 \pi r. \frac{dr}{dt}

The rate of change of the radius is given as
\frac{dr}{dt} =-2 \,  \frac{ft}{s}
Therefore
\frac{dA}{dt} =-4 \pi r \,  \frac{ft^{2}}{s}

When r = 10 ft, obtain
\frac{dA}{dt}|_{r=10 \, ft} = -40 \pi  \,  \frac{ft^{2}}{s}

Answer: - 40π ft²/s (or - 127.5 ft²/s)
7 0
3 years ago
Which statement is TRUE concerning the particle arrangement of a solid
Anni [7]
It's packed together
8 0
3 years ago
Read 2 more answers
Technician A says that the accumulator is on the high-pressure side of the refrigerant system. Technician B says that the receiv
pychu [463]

Question:

The options are

a. Technician A only

b. Technician B only

c. Both A and B

d. Neither A nor B

Answer:

The correct option is

d. Neither A nor B

Explanation:

Here, we note that to locate the receiver/driers we look at the high-pressure side of refrigerant system normally around the tubes in between the expansion valve outlet and the condenser outlet and connected to the condenser.

While the accumulator can be found, attached to the evaporator outlet within the low pressure side of the refrigerant system.

Therefore, neither Technician A nor B is correct.

6 0
2 years ago
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