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goldfiish [28.3K]
3 years ago
8

If you could please answer the questions A,B,C Not D. Image attached below

Physics
1 answer:
Rina8888 [55]3 years ago
4 0
A. Mass

b. Car's Kinetic Energy

c. Kinetic energy is the energy an object has due to its motion. The kinetic energy of an object is calculated from the velocity and the mass of the object.
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A high frequency sound will have a ?
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The frequency of a sound wave is what your ear understands as pitch. A higher frequency sound has a higher pitch and the lower the period

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Blocks A (mass 2.00 kg) and B (mass 10.00 kg, to the right of A) move on a frictionless, horizontal surface. Initially, block B
olga2289 [7]

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3 years ago
Which fact was most likely discovered between the time of Mendeleev’s table and the time of Moseley’s table that helped Moseley
igomit [66]

Answer:

The number of protons in an atom is different than the atom's total mass.

Explanation:

Mendeleev had presented the first structured periodic table in 1869. But, in 1913, Henry Moseley developed the modern periodic table. The crucial difference between the two periodic tables is that Mendeleev's periodic table is generated on the basis of the atomic masses of chemical elements while the chemical element's atomic numbers were the main focus of Moseley's periodic table. There were just 56 chemical elements in Mendeleev's periodic table. On the other hand, 74 chemical elements are presented in Moseley's periodic table.

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3 years ago
In 2000, NASA placed a satellite in orbit around an asteroid. Consider a spherical asteroid with a mass of 1.40×1016 kg and a ra
Arturiano [62]

A) 8.11 m/s

For a satellite orbiting around an asteroid, the centripetal force is provided by the gravitational attraction between the satellite and the asteroid:

m\frac{v^2}{(R+h)}=\frac{GMm}{(R+h)^2}

where

m is the satellite's mass

v is the speed

R is the radius of the asteroide

h is the altitude of the satellite

G is the gravitational constant

M is the mass of the asteroid

Solving the equation for v, we find

v=\sqrt{\frac{GM}{R+h}}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}

M=1.40\cdot 10^{16}kg

R=8.20 km=8200 m

h=6.00 km = 6000 m

Substituting into the formula,

v=\sqrt{\frac{(6.67\cdot 10^{-11})(1.40\cdot 10^{16}kg)}{8200 m+6000 m}}=8.11 m/s

B) 11.47 m/s

The escape speed of an object from the surface of a planet/asteroid is given by

v=\sqrt{\frac{2GM}{R+h}}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}

M=1.40\cdot 10^{16}kg

R=8.20 km=8200 m

h=6.00 km = 6000 m

Substituting into the formula, we find:

v=\sqrt{\frac{2(6.67\cdot 10^{-11})(1.40\cdot 10^{16}kg)}{8200 m+6000 m}}=11.47 m/s

5 0
3 years ago
An electron is in motion at 4.0 × 10^6 m/s horizontally when it enters a region of space between two parallel plates, starting a
Archy [21]

Answer:

Explanation:

Given that  

speed u=4×10⁶ m/s

electric field E=4×10² N/c

distance b/w the plates d=2 cm

basing on the concept of the electrostatices

now we find the acceleration b/w the plates

acceleration a=qE/m=1.6×10⁻¹⁹×4×10²/9.1×10⁻³¹=0.7×10¹⁴=7×10¹³ m/s

now we find the horizantal distance travelled by electrons hit the plates

horizantal distance X=u[2y/a]^1/2

=4×10⁶[2×2×10⁻²/7×10¹³]^1/2

=9.5cm

now we find the velocity f the electron strike the plate

v²-(4×10⁶)²=2×7×10¹³×2×10⁻²

v²=16×10¹²+28×10¹¹

v²=1.88×10¹³m/s

speed after hits =>V=4.34×10⁶ m/s

7 0
4 years ago
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