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AlekseyPX
1 year ago
4

Which expression is equiavalent to 7(-3x-2)

Mathematics
1 answer:
lukranit [14]1 year ago
6 0

−21x−14 

Step-by-step explanation:

Multiply the single term 77 by each term of the polynomial \left(-3x-2\right)(−3x−2)

-21x-14−21x−14

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I need a teachers help! are there any teachers here? I really need help!
bearhunter [10]

Answer:

Not me sry

Step-by-step explanation:

TNX for the free points tho

7 0
3 years ago
Evaluate 4 − 0 . 2 5 g + 0 . 5 h 4−0.25g+0.5h4, minus, 0, point, 25, g, plus, 0, point, 5, h when g = 1 0 g=10g, equals, 10 and
abruzzese [7]

Not sure about the weird echo in the question but I think we're being ask to evaluate

4 - 0.25g + 0.5h

when g=10, h=5

That's

4 - 0.25(10) + 0.5(5) = 4 - 2.5 + 2.5 = 4

Answer: 4


6 0
3 years ago
Read 2 more answers
Find the area of the shapes
Dmitry [639]

Answer:

1. 800 cm squared

2. 152 cm squared

Step-by-step explanation:

let break it down

1. 800 cm squared

20 * 7 = 140

20 * 6 = 120

38 - 20 = 18

30 * 18 = 540

now add all of them together

140 + 120 + 540

100 + 100 + 500 = 700

40 + 20 + 40 = 100

700 + 100 = 800 cm squared

2. 152 cm squared

16 * 10 = 160

2 * 2 + 2 * 2 = 4 + 4 = 8

160 - 8 = 152 cm squared

5 0
3 years ago
How many circles have a center of (4,7)?
nikklg [1K]
Any circle that can given by

(x-4)^{2}+(y-7)^{2}=r^{2}

have a center of (4,\;7).


You can choose any positive value for the radius r. Hence, there are infinity circles.

6 0
4 years ago
Evaluate log 2 base 8​
iren2701 [21]

Answer:  The correct answer is:  " 3 " .

_______________________________

Step-by-step explanation:

_______________________________

The problem given is:

_______________________________

Evaluate:  log 2 base 8 .

_______________________________

Rewrite as:  " log_2}8 = ? _______________  " ;  log_2}8 = ? _______________

_______________________

Take note of the following definition of a logarithm:

_______________________

"   log_{m}n = a " ;  ↔  " m^{a} =n  "  ;

_______________________

in which:  m  refers to the "base" ;

               n  refers to the "argument" ;

               a  refers to the "exponent" ;

______________________________

As such:

       " log_2}8 = ? _______________ "

      ⇔ " 2^{x} = 8 " ; Solve for "x" ;  

 _______________

 Note:  

  2⁰ = 1 ;

  2¹ = 2 ;

  2² = 2 * 2 = 4 ;

  2³ = 2 * 2 * 2 = 8 .

___________________

 → " 2^{x} = 8 " ;

 → " 2^{3} = 8 " ;  since: " 2^{3} = 2  *2 *2 = 8 " ;

 → as such:   " x = 3  " ;

______________________

Thus:

"log 2 base 8 " ;

          = log{_{2}}8 = 3  .

_______________________

Hope this helps!

Best wishes to you!

3 0
3 years ago
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