In resonance structures, the chemical connectivity in the molecule is same but the distribution of electrons are different around the structure. They are created by moving electrons in double or triple bonds, and not atoms.
Phenol,
and methanol,
both are alcohols that contain an
group attached to carbon atom.
Due to loss of 1
from phenol, it forms phenoxide anion and due to presence of double bond in the benzene ring the negative charge on the oxygen atom (which represents electrons) will resonate with double bonds of benzene ring as shown in the image. The resonance-stabilized phenoxide ion is more stable. Whereas when methanol lose 1
it forms methoxide anion and there are no such electrons present in the structure of methoxide that will result in the movement of electron. Since, due to resonance-stabilized phenoxide ion is more stable than methoxide ion, so it is a stronger acid.
The structures of the anions resulting from loss of 1
from phenol and methanol is shown in the image.
Answer:
Option 3.
Explanation:
Alkenes are generally unsaturated hydrocarbon with carbon to carbon double bond (C=C).
From the options given above, only option 2 and 3 contain carbon to carbon double bond (C=C).
Option 2 is called a benzene ring and not an alkene. Benzene are not classified as alkenes because the double bond between the carbon can not be broken i.e benzene does not undergo addition reaction like the alkenes. Benzene tends to show more stability than the alkenes.
This leaves us with option 3 as the answer to the question because it contains carbon to carbon double bond (C=C)
Answer:
A. 97.8 mm
Explanation:
There are 10 divisions between 9 cm (90 mm) and the end of the ruler (10 cm or 100 mm).
Each division equals 1 mm.
Each 5 mm mark has a longer tick, and the dashed red line is between the 97 mm and 98 mm marks.
You would normally estimate to the nearest tenth of a division. An estimate of 0.8 mm is reasonable.
The length of the object is 97.0 mm + 0.8 mm = 97.8 mm.
B is wrong. You can't possibly estimate to the nearest hundredth of a division.
C is wrong. The dashed red line slightly before the 98 mm mark.
D is wrong. If the dashed red line were exactly on the 98 mm mark, you would record the measurement as 98.0 mm. This indicates that you measured the object to zero tenths on either side of the mark.
The physical explanation is that increasing temperature increases the kinetic energy of the gas molecules. Hence, their random motion breaks more intermolecular bonds and the gas is less dissolved in the solvent. In contrast, solid solutes in water have increased solubility with increased temperatures.
Remember that density refers to the "mass per unit volume" of an object.
So, if an object had a mass of 100 grams and a volume of 100 milliliters, the density would be 100 grams / 100 ml.
In the question, water on the surface of the scale would add weight, so the mass of the object that you're weighing would appear to be heavier than it really is. If that happens, you'll incorrectly assume that the density is GREATER than it really is
As an example, suppose that there was 5 ml of water on the surface of the scale. Water has a density of 1 gram per milliliter (1 g/ml) so the water would add 5 grams to the object's weight. If we use the example above, the mass of the object would seem to be 105 grams, rather than 100 grams. So, you would calculate:
density = mass / volume
density = 105 grams / 100 ml
density = 1.05 g/ml
The effect on density would be that it would erroneously appear to be greater
Hope this helps!
Good luck