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anzhelika [568]
1 year ago
14

Identify the missing coefficient in the balanced equation and classify the type of reaction.

Chemistry
2 answers:
Scilla [17]1 year ago
6 0

Answer:

Explanation:

Part A

Balancing means that the same number of elements on one side of the equation must be the same as the number of elements on the other side.

You need 3 carbons on the right side because right now there is only one. Try putting a 3 in front of the CO2 and see if the oxygens come into balance as well.

Al2(CO3)3 ⟶ Al2O3 + ___CO2

Al2(CO3)3 ⟶ Al2O3 + 3CO2

Balance check

Element                Left           Right

Al                            2                2

Carbon(C)              3                3

Oxygen                  9               3 + 6 = 9

And it is balanced.

Part B

It's a decomposition of some kind. Two smaller molecules are created from one larger one.

Montano1993 [528]1 year ago
3 0
I think it is decomposition because it processes in which chemical species break up into simpler parts.
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Which of the following statements are true regarding the dissociation of Al(NO3)3? Select more than one
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Answer:

There will be one Al3+ ion.

There will be 3 NO3- ions

Explanation:

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Al(NO₃)₃   →  Al³⁺ + 3NO₃¹⁻

When aluminium nitrate dissociate it produces one silver ion (Al³⁺) and three (NO₃¹⁻) ions.

Properties of Al(NO₃)₃:

It is inorganic compound having molecular mass 169.87 g/mol.

It is white odor less compound.

Its density is 4.35 g/mL.

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4 0
2 years ago
Hiii please help me to balance the chemical equation:
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Explanation:

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Prove how the Law Conservation of Mass and Enery apply to Cellular Respiration​
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A mole of a substance has a mass in grams that is equal to the molecular mass. For example, a carbon atom has a mass of 12.01 u.
IRINA_888 [86]

Answer:

M(Fe₂O₃) = 159.70 g/mol

M(CO) = 28.01 g/mol

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Explanation:

We can calculate the molar mass of a compound by summing the molar masses of the elements that form it.

Fe₂O₃

M(Fe₂O₃) = 2 × M(Fe) + 3 × M(O) = 2 × 55.85 g/mol + 3 × 16.00 g/mol = 159.70 g/mol

CO

M(CO) = 1 × M(C) + 1 × M(O) = 1 × 12.01 g/mol + 1 × 16.00 g/mol = 28.01 g/mol

Fe

M(Fe) = 1 × M(Fe) = 1 × 55.85 g/mol = 55.85 g/mol

CO₂

M(CO₂) = 1 × M(C) + 2 × M(O) = 1 × 12.01 g/mol + 2 × 16.00 g/mol = 44.01 g/mol

3 0
3 years ago
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