The average speed of the plane is 875.999 m/s.
Average speed can be defined as the ratio of total distanced travelled by the object to that of total time taken to cover the distance.
Mathematically, Average speed = Av =
According to the question,
Speed of the plane away from its base V₁ = 730 m/s
Speed of the plane when it flies back V₂ = 1095 m/s
Plane flies the distance D = 404 km
Total Distance covered by the plane S = 404 * 2 km
(because the distance travelled by the plane when going away from the base and then flying back to the base is same)
Therefore S = 808 km = 808 ˣ 10³ m
Time taken by the plane while flying away from the base T₁ =
T₁ = = 553.425 s
Time taken by the plane while flying back to the base T₂ =
T₂ = = 368.949s
Total Time T = T₁ + T₂ = 922.375 s
Therefore Av =
= m/s
= m/s
= 875.999 m/s
The average speed of the plane will be 875.999 m/s.
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Answer : The average speed of the sprinter is, 34.95 Km/hr
Solution :
Average velocity : It is defined as the distance traveled by the time taken.
Formula used for average velocity :
where,
= average velocity
d = distance traveled = 200 m
t = time taken = 20.6 s
Now put all the given values in the above formula, we get the average velocity of the sprinter.
conversion :
(1 Km = 1000m)
(1 hr = 3600 s)
Therefore, the average speed of the sprinter is, 34.95 Km/hr