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Tems11 [23]
1 year ago
12

Can someone put their own numbers in this sentence and solve it? Thanks!

Chemistry
1 answer:
Nat2105 [25]1 year ago
4 0

A balloon with a pressure of 1 atm and a temperature of 17° Celsius has a volume of 1000 mL. The day warms up and increases the temperature to 27° Celsius, which makes the pressure change to 1520 mm Hg.What is the new volume of the balloon, in Liters?

The new volume of the balloon is <u>0.517 L.</u>

By ideal gas law, PV = nRT

P = pressure

V = volume

n = number of mole of gas

R = gas constant

T = temperature

Using ideal gas law, P₁V₁/ T₁ = P₂V₂/ T₂

P₁= 1 atm

V₁ = 1000 mL = 1 L

T₁ = 17° C = 290 K

After the day warms up:-

P₂ = 1520 mm Hg = 2 atm

T₂ = 27° C = 300 K

Put these values in formula, P₁V₁/ T₁ = P₂V₂/ T₂

V₂ =  P₁V₁T₂/ T₁ P₂

V₂ = 1 atm× 1 L × 300 K/ 290 K × 2 atm

V₂ = 0.517 L = 517 mL

Hence, the new volume of the balloon is 0.517 L.

The ideal gas equation is formulated as: PV = nRT.

In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the overall quantity of ideal gas this is measured in terms of moles, R is the universal gas constant, and T is the temperature.

Learn more about ideal gas law here:- brainly.com/question/25290815

#SPJ1

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At a festival, spherical balloons with a radius of 280. Cm are to be inflated with hot air and released. The air at the festival
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Answer:

8608.18 balloons

Explanation:

Hello! Let's solve this!

Data needed:

Enthalpy of propane formation: 103.85kJ / mol

Specific heat capacity of air: 1.009J · g ° C

Density of air at 100 ° C: 0.946kg / m3

Density of propane at 100 ° C: 1.440kg / m3

First we will calculate the propane heat (C3H8)

3000g * (1mol / 44g) * (103.85kJ / mol) * (1000J / 1kJ) = 7.08068 * 10 ^ 6 J

Then we can calculate the mass of the air with the heat formula

Q = mc delta T

m = Q / c delta T = (7.08068 * 10 ^ 6 J) / (1.009J / kg ° C * (100-25) ° C) =

m = 93566.96kg

We now calculate the volume of a balloon.

V = 4/3 * pi * r ^ 3 = 4/3 * 3.14 * 1.4m ^ 3 = 11.49m ^ 3

Now we calculate the mass of the balloon

mg = 0.946kg / m3 * 11.49m ^ 3 = 10.87kg

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93566.96kg / 10.87kg = 8608.18 balloons

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