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1 year ago

Can someone put their own numbers in this sentence and solve it? Thanks!

1 answer:

4 0

A balloon with a pressure of 1 atm and a temperature of 17° Celsius has a volume of 1000 mL. The day warms up and increases the temperature to 27° Celsius, which makes the pressure change to 1520 mm Hg.What is the new volume of the balloon, in Liters?

The new volume of the balloon is 0.517 L.

By ideal gas law, PV = nRT

P = pressure

V = volume

n = number of mole of gas

R = gas constant

T = temperature

Using ideal gas law, P₁V₁/ T₁ = P₂V₂/ T₂

P₁= 1 atm

V₁ = 1000 mL = 1 L

T₁ = 17° C = 290 K

After the day warms up:-

P₂ = 1520 mm Hg = 2 atm

T₂ = 27° C = 300 K

Put these values in formula, P₁V₁/ T₁ = P₂V₂/ T₂

V₂ = P₁V₁T₂/ T₁ P₂

V₂ = 1 atm× 1 L × 300 K/ 290 K × 2 atm

V₂ = 0.517 L = 517 mL

Hence, the new volume of the balloon is 0.517 L.

The ideal gas equation is formulated as: PV = nRT.

In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the overall quantity of ideal gas this is measured in terms of moles, R is the universal gas constant, and T is the temperature.

Learn more about ideal gas law here:- brainly.com/question/25290815

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You might be interested in

If you want to use a serial dilution to make a 1/50 dilution. The first dilution you make is a 1/5 dilution with a total volume

fomenos

Answer:

Explanation:

A serial dilution is a dilution that is made fractionated. The stock solution is diluted, then this now solution is diluted, and then successively. The final dilution is the multiplication of the steps dilutions.

The representation of the dilution is v/v (volume per volume) indicates how much of the stock solution is in the total volume of the solution. So 1/5 indicates 1 mL to 5 mL of the solution. If the final volume must be 1 mL, then the stock solution must be 0.2 mL (0.2/1 = 1/5), and the volume of the solvent is 1 mL - 0.2 = 0.8 mL.

The second solution is done with a dilution of 1/10 or 1 mL of the first solution in 10 mL of the total solution. Because the solution has 1 mL, then the volume of the first solution must be 0.1 mL (0.1/1 = 1/10), and the volume of the solvent that must be added is 1 mL - 0.1 mL = 0.9 mL.

5 0

2 years ago

What is the empirical formula of a compound with a percent composition of 22.5% Phosphorous and 77.5% Chlorine?

sashaice [31]

Answer:

$\boxed {\boxed {\sf PCl_3}}$

Explanation:

We are given the percent composition: 22.5% phosphorus and 77.5% chlorine.

We can assume there are 100 grams of this compound. We choose 100 because we can simply use the percentages as the masses.

22.5 g P
77.5 g Cl

Next, convert these masses to moles, using the molar masses found on the Periodic Table.

P: 30.974 g/mol
Cl: 35.45 g/mol

Use the molar masses as ratios and multiply by the number of grams. $22.5 \ g \ P * \frac {1 \ mol \ P }{30.974 \ g \ P}= \frac {22.5 \ mol \ P }{ 30.974} = 0.7264157035 \ mol \ P$

$77.5 \ g \ Cl * \frac {1 \ mol \ Cl }{35.45 \ g \ Cl}= \frac {77.5 \ mol \ Cl }{ 35.45} \ =2.186177715 \ mol \ Cl$

Divide both of the moles by the smallest number of moles to find the mole ratio.

$\frac {0.7264157035} {0.7264157035} = 1$

$\frac {2.186177715}{0.7264157035}=3.009540824 \approx 3$

The mole ratio is about 1 P: 3 Cl, so the empirical formula is written as: PCl₃

4 0

2 years ago

How many significant digits are in the number 2370.0?

xz_007 [3.2K]

Answer:

2370.0 contains 4 significant digits and Option (c) is correct .

1.20\times 10^{-3}\ contains\ three\ significant\ digit.

Option (b) is correct .

Step-by-step explanation:

Rules for finding significant digit .

1 : Non-zero digits are always significant.

2: Any zeros between two significant digits are significant .

3: Trailing zeros in the decimal number is also significant.

As the number given be 2,370.0.

= \frac{23700}{10}

Simplify the above

= 2370

Thus by using the rule given above.

2370.0 contains 4 significant digits.

Option (c) is correct .

As the number given be 0.00120 .

= \frac{120}{100000}

Simplify the above

= \frac{1.20}{1000}

= 1.20\times 10^{-3}

Thus by using the rule given above.

1.20\times 10^{-3}\ contains\ three\ significant\ digit.

Option (b) is correct .

4 0

2 years ago

Read 2 more answers

N2 + 3H2, -> 2NH3 If I have 50.6 L of N2 and excess H2, how many liters of NH3 can I produce?

Anastaziya [24]

Answer:

C. 101.2 L

Explanation:

N2 + H2= NH3

Balancing it,

N2 + 3 H2 = 2.NH3

(1 mol) (3 mol) (2 mol)

which means

1 molecule of nitrogen reacts with 3 molecule of hydrogen to form ammonia.

Likewise,

50.6 l of nitrogen reacts with 50.6 × 3= 151.8 l of hydrogrn to form 50.6 × 2= 101.2 l of ammonia.

3 0

2 years ago

How many moles and molecules are there in 250g of hydrogen nitrate, HNO3

Viefleur [7K]

Answer:

Number of molecules = 23.9 × 10²³ molecules

Number of moles = 3.97 mol

Explanation:

Mass of HNO₃ = 250 g

Number of moles = ?

Number of molecules = ?

Solution:

Number of moles = mass / molar mass

Number of moles = 250 g/63 g/mol

Number of moles = 3.97 mol

Number of molecules:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 250 g of HNO₃:

250 g/ 63 g/mol = 3.97 mole

3.97 × 6.022 × 10²³ molecules = 23.9 × 10²³ molecules

6 0

2 years ago