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3 years ago

A change in which property of light will have no effect on weather or not the photoelectric effect occurs

Chemistry

1 answer:

lubasha [3.4K]3 years ago

7 0

It's C. intensity. If it's not correct, please tell me.

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How do you find the molar mass of a hydrate

Darya [45]

If you mean hydrate as in <em>MgSO4 · 7H2O, </em>then simply find the molar mass of each element you see.

For the example above, that means you would add the molar mass (found on the periodic table) of Mg, then S, then 4(O), 14(H), and 7(O).

The results would be your molar mass for the hydrate.

I hope this is what you meant by your question!

6 0

2 years ago

Salts usually have a low melting point true or false

antoniya [11.8K]

Hello!

This is false!! It is the other way around. They usually have a very high melting point. For example table salt is around 800deg C which is approx just under 1500deg F.

Hope this helps. Thank you

3 0

3 years ago

How to figure out mass and moles of a product

Lyrx [107]

Answer:

In order to calculate the moles of a product, you must know the mass of the product, and its molar mass (g/mol), which is the mass of one mole of of the product. You then divide the mass of the product by its molar mass.

6 0

2 years ago

Acids containing polyatomic ions are named according to the name of the anion. true or false

Ray Of Light [21]

Answer:

true

Explanation:

Names for such acids consist of the prefix “hydro-“, the first syllable of the anion, and the suffix “-ic”. Complex acid compounds have oxygen in them. For an acid with a polyatomic ion, the suffix “-ate” from the ion is replaced with “-ic.”

5 0

2 years ago

A certain substance X has a normal freezing point of −3.1°C and a molal freezing point depression constant =Kf·6.23°C·kgmol−1. C

muminat

Answer:

Freezing T° of solution = - 7.35 °C

Explanation:

This is about the freezing point depression, a colligative property which depends on solute.

The formula is: Freezing T° pure solvent - Freezing T° solution = m . Kf . i

Freezing T° of pure solvent is -3.1°C

At this case, i = 1. As an organic compound the urea does not ionize.

We determine the molality (mol/kg of solvent)

We convert mass to moles:

12.3 g . 1mol / 60.06 g = 0.205 moles

0.205 mol / 0.3 kg = 0.682 mol/kg

We replace data in the formula:

-3.1°C - Freezing T° of solution = 0.682 mol/kg . 6.23 kg°C/mol . 1

Freezing T° of solution = 0.682 mol/kg . 6.23 kg°C/mol . 1 + 3.1°C

Freezing T° of solution = - 7.35 °C

6 0

3 years ago